Answer:
x=15 and y=2
Step-by-step explanation:
The given system of equations is
8y - x = 1 ...............(i)
and
10 y = x + 5 ...............(ii)
Now from equation (ii)
10 y = x + 5
subtracting -5 from both sides
10 y - 5 = x + 5 - 5
10 y -5 = x
or
x = 10y -5 ............(iii)
Put this in equation (i)
it becomes
8y - (10y -5) = 1
8y-10y+5=1
-2y+5 =1
subtracting 5 from both sides
-2y + 5 -5 = 1 -5
-2y = -4
dividing both sides by -2 gives
-2y / -2 = -4 / -2
y = 2
We got the value of y putting it in equation (iii) to get the value of x
as from equation (iii)
x = 10y-5
x = 10(2) - 5
x = 20 -5
x = 15
So this is the solution from the equations
To be a triangle
1)sum of two sides should be more than 3d side,
2) 3d side should be more than difference of two other sides.
5+13 > x, ----> x < 18
13 - 5 < x, -----> x > 8
8< x < 18
It looks like only one value of the side can create a triangle,
F.10
You’re trying to get the first equation to equal y so you can substitute it in the second question
2x + y = -2
subtract 2x from both sides: y = -2 - 2x
rearrange the equation : -2x -2
so the answer is C
Answer:
The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.
Step-by-step explanation:
Standardized score, z = (x - xbar)/s
xbar = mean, s = standard deviation.
For the first test, x = 271.2, xbar = 240, s = 24
z = (271.2 - 240)/24 = 1.3
For the second test, x = 63.6, xbar = 60, s = 6
z = (63.6 - 60)/6 = 0.6
The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.
Hope this Helps!!!