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3 years ago

The hypotenuse of an isosceles triangles measures 10 inches long. What is the length of one leg of the triangle?

Mathematics

2 answers:

Bingel [31]3 years ago

8 0

The leg sides are or at least one is (10 in.)/√(2) = 10√(2)/2 in. = 5√(2) long.

Aloiza [94]3 years ago

3 0

Let one leg be x. Hypotenuse = 10

x² + x² = 10²

2x² = 10²

<span>2x² = 100
</span>
<span>x² = 100/2
</span>
x² = 50

x = √50

x = √(25 *2)

x = √25 * √2 = 5√2

x = 5√2 ≈ 5*1.414 = 7.07

Length of each leg ≈ 7.07

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