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faust18 [17]
3 years ago
12

The hypotenuse of an isosceles triangles measures 10 inches long. What is the length of one leg of the triangle?

Mathematics
2 answers:
Bingel [31]3 years ago
8 0
The leg sides are or at least one is (10 in.)/√(2) = 10√(2)/2 in. = 5√(2) long.
Aloiza [94]3 years ago
3 0
Let one leg be x.    Hypotenuse = 10

x² + x² = 10²

2x² = 10²

<span>2x² = 100
</span>
<span>x² = 100/2
</span>
x² = 50

x = √50

x = √(25 *2)

x = √25 * √2 = 5√2

x = 5√2 ≈ 5*1.414 = 7.07

Length of each leg ≈ 7.07
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Further explanation:

Given equation of line is:

6x+y=3\\y= -6x+3

The co-efficient of x is the slope of given line.

Let m1 be the slope of given line

and

m2 be the slope of line perpendicular to given line

Then

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Product of slopes of perpendicular lines is -1

m_1*m_2 = -1\\-6*m_2=-1\\m_2=\frac{-1}{-6}\\m_2=\frac{1}6}

The equation of new line can be written as:

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To find the value of b, we will put (-6,7) in equation

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Putting the values of b and m in general equation

y=\frac{1}{6}x+8

Keywords: Slope, Point-slope form, perpendicular lines

Learn more about perpendicular lines at:

  • brainly.com/question/12941985
  • brainly.com/question/4152194

#LearnwithBrainly

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