Given the function below, if h(x)=−4, find x. h(x)=−6x+20

TiliK225 [7]

Step-by-step explanation:

You didn't provide any numbers but in order to find the median of something you order a given list of numbers from least to greatest. After you've done this you find the number located in the middle of the number set. If there are two numbers in the middle then you add them together and divide that number by two.

Hope this helps.

8 0

4 years ago

last year the cost of a season ticket for a rugby club £370. This year the cost of a season ticket for the club has been increas

Elden [556K]

Answer:

$\frac{80}{370}$ OR $\frac{8}{37}$

Step-by-step explanation:

So first you find the difference between the new cost and the old cost:

450 - 370 = 80

So the increase was 80.

When you write it as a fraction you write the increase ( 80 ) over the starting cost ( 370 ).

Thus the answer becomes $\frac{80}{370}$

But you can always reduce it to its lowest terms thus:

$\frac{8}{37}$

HOPE THIS HELPED

4 0

3 years ago

Factor this polynomial completely.

azamat

Answer:

(x-4) (x-4)

Step-by-step explanation:

foil [first, outside, inside, last]

x^2 -8x = 16

(x-4) (x-4) = x^2 -4x -4x +16 = x^2 -8x +16

3 0

3 years ago

Read 2 more answers

The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75

KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

$\mu = 47$

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

$4\sigma = 75 - 19$

$4\sigma = 56$

$\sigma = \frac{56}{4} = 14$

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 47}{14}$

$Z = -1.57$

$Z = -1.57$ has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 47}{14}$

$Z = 0.93$

$Z = 0.93$ has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

3 0

3 years ago

8x^3-22x^2-4 divided by 4x-3

MA_775_DIABLO [31]

The answer is 24 because 8 times 3 is 24

3 0

3 years ago