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Alexus [3.1K]
3 years ago
12

last year the cost of a season ticket for a rugby club £370. This year the cost of a season ticket for the club has been increas

e to £450. write down the increase in the cost of season ticket as a fraction of last years cost.
Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Answer:

\frac{80}{370} OR \frac{8}{37}

Step-by-step explanation:

So first you find the difference between the new cost and the old cost:

450 - 370  = 80

So the increase was 80.

When you write it as a fraction you write the increase ( 80 ) over the starting cost ( 370 ).

Thus the answer becomes \frac{80}{370}

But you can always reduce it to its lowest terms thus:

\frac{8}{37}

HOPE THIS HELPED

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Raheem's entire workout consisted of 15 minutes of warm-up exercises, 30 minutes of lifting weights,and 45 minutes on the treadm
Sindrei [870]

Answer:

b

Step-by-step explanation:

Time taken for the total workout = 15 + 30 + 45 = 90 minutes

Time taken for lifting weight : total time = 30 : 90

                                                                 = 1 : 3

4 0
3 years ago
The following function represents the profit P(n), in dollars, that a concert promoter makes by selling tickets for n dollars ea
Gre4nikov [31]
A) zeroes

P(n) = -250 n^2 + 2500n - 5250

Extract common factor:

P(n)= -250 (n^2 - 10n + 21)

Factor (find two numbers that sum -10 and its product is 21)

P(n) = -250(n - 3)(n - 7)

Zeroes ==> n - 3 = 0  or n -7 = 0
Then n = 3 and n = 7 are the zeros.

They rerpesent that if the promoter sells tickets at 3  or 7 dollars the profit is zero.

B) Maximum profit

Completion of squares

n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4

P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000

Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000

Maximum profit =1000 at n = 5

C) Axis of symmetry

Vertex = (h,k) when the equation is in the form A(n-h)^2 + k

Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000

Vertex = (5, 1000) and the symmetry axis is n = 5.



8 0
3 years ago
Does anyone know how to do this?? steps are helpful but not necessary
aniked [119]

Answer:

C.  \frac{2(x+16)}{x+4}

Step-by-step explanation:

We want fg of x, so first we have to multiply f(x) times g(x).

\frac{x+16}{x} * \frac{2x}{x+4}

\frac{(x+16)2x}{x(x+4)}

\frac{2x^{2}+32x}{x^{2}+4x}

We can cancel out an x from every term.

\frac{2x+32}{x+4}

Let's rewind a little to get this into one of the answer choices.

\frac{2(x+16)}{x+4} is our answer.

6 0
3 years ago
What property is occurring in the following example? 11.5 + (- 11.5) = 0
kramer

Answer: A property occurring in the example 11.5 + (-11.5) = 0, is additive inverse.

Step-by-step explanation:

A property where sum of any number and its inverse is equal to zero is called additive inverse property.

For example, 11.5 + (-11.5) = 0

Here, 11.5 is the number and its inverse is (-11.5). The sum of both these is equal to zero. Hence, it shows a property of additive inverse.

Thus, we can conclude that property occurring in the example 11.5 + (-11.5) = 0, is additive inverse.

5 0
3 years ago
How many unique ways are there to arrange the letters in the word DEN?
Tatiana [17]
2 is the correct answer I'm almost definite
5 0
3 years ago
Read 2 more answers
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