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Alexus [3.1K]
3 years ago
12

last year the cost of a season ticket for a rugby club £370. This year the cost of a season ticket for the club has been increas

e to £450. write down the increase in the cost of season ticket as a fraction of last years cost.
Mathematics
1 answer:
Elden [556K]3 years ago
4 0

Answer:

\frac{80}{370} OR \frac{8}{37}

Step-by-step explanation:

So first you find the difference between the new cost and the old cost:

450 - 370  = 80

So the increase was 80.

When you write it as a fraction you write the increase ( 80 ) over the starting cost ( 370 ).

Thus the answer becomes \frac{80}{370}

But you can always reduce it to its lowest terms thus:

\frac{8}{37}

HOPE THIS HELPED

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Paladinen [302]

Answer:

37

Step-by-step explanation:

The cosine of an angle is the length of the adjacent side, in this case x, divided by the length of the hypotenuse, in this case 85. So you can set up the following equation:

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Hope this helps!

6 0
3 years ago
Given that 3^-n=0.2<br> Find the value of (3^n)^2
dybincka [34]

Step-by-step explanation:

3^-n=0.2

1/3^n=0.2

1=0.2(3^n)

3^n=1/0.2

3^n=5

(3^n)²=5²

(3^n)²=25

7 0
3 years ago
The Janie Gioffre Drapery Company makes three types of draperies at two different locations. At location I, it can make 10 pairs
Tcecarenko [31]

Answer:

  • 30 days at location I
  • 35 days at location II

Step-by-step explanation:

Let x and y represent days of operation of Location I and Location II, respectively. Then we want to minimize the objective function ...

  650x +750y

subject to the constraints on drape production:

  10x +20y ≥ 1000 . . . . . order for deluxe drapes

  20x +50y ≥ 2100 . . . . . order for better drapes

  13x +6y ≥ 600 . . . . . . . order for standard drapes

__

I find a graphical solution works well for this. The vertices of the feasible solution space are (x, y) = (0, 100), (30, 35), (80, 10), (105, 0). The vertex at which the cost is minimized is

  (x, y) = (30, 35)

This schedule will produce exactly the required numbers of deluxe and standard drapes, and 2350 pairs of better drapes, 250 more than required.

_____

In the attached graph, we have reversed the inequalities so that the solution space (feasible region) is white, not triple-shaded. Minimizing the objective function means choosing the vertex of the feasible region so that the line representing the objective function is as close to the origin as possible.

4 0
3 years ago
Find x. Leave answers in simplified radical form. (Step by step)
just olya [345]

Answer:

\sf x  = 4\sqrt{2}

Given:

  • adjacent: 4 cm
  • hypotenuse: x cm
  • angle: 45°

<u>using cosine rule:</u>

\sf cos(x)  = \dfrac{adjacent}{hypotenuse}

\sf cos(45)  = \dfrac{4}{x}

\sf x  = \dfrac{4}{cos(45)}

\sf x  = 4\sqrt{2}

4 0
3 years ago
Read 2 more answers
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