You have 3 pairs of shorts,8 shirts, and 3 pairs of shoes.How many different outfits can you make?

MA_775_DIABLO [31]

Alright, you had it right the first time, the answer is F) 72

8 0

2 years ago

The units of the subway map below are in miles. Suppose the routes between stations are straight. Station G, not shown on the

slega [8]

Answer:

8.60 miles

Step-by-step explanation:

If S=station G, not shown on the map, is 5 miles east and 7 miles south of Station A, the approximate distance between Station E and Station G when traveling by subway will be gotten using the Pythagoras theorem.

EG² = 5²+7²

EG² = 25+49

EG² = 74

EG = √74

EG = 8.60 miles

<em>Hence the approximate distance between Station E and Station G when traveling by subway is 8.60miles</em>

7 0

2 years ago

Lara rides her skateboard 228 feet in 2 minutes what is her speed

Oliga [24]

Answer:

114 ft per minute

Step-by-step explanation:

To find the speed, take the distance and divide by the time

228 ft/ 2 minutes

114 ft per minute

7 0

2 years ago

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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

You notice a hot air balloon descending. The elevation h (in feet) of the balloon is modeled by the function h(x)=−11x+330, wher

Mars2501 [29]

Answer:

1) Please find attached, the graph of the function

The domain of the function is 0 ≤ x ≤ 30

The range of the function is 330 ≥ x ≥ 0

2) The slope of the given equation, shows that the elevation decreases, by (-)11 feet for each increase in time by one second

3) The y-intercept gives the initial elevation of the balloon at time t = 0 seconds

The x-intercept gives the final elevation of the balloon when it lands at time t = 30 seconds

Step-by-step explanation:

1) The function modelling the height of the balloon is h(x) = -11x + 330

Where;

x = The time of elevation of the balloon

The data for the graphing derived from Microsoft Excel are as follows

x ${}$ h(x)

0 ${}$ 330

5 ${}$ 275

10 ${}$ 220

15 ${}$ 165

20 ${}$ 110

25 ${}$ 55

30 ${}$ 0

Please find attached, the graph of the function

The domain of the function is 0 ≤ x ≤ 30

The range of the function is 330 ≥ x ≥ 0

Comparing the given function to the general equation of a straight line, y = m·x + c, we have that the slope, m = -11

2) The slope of a straight line graph gives the rate of change of the dependent variable, per unit change in the independent variable

Therefore, the slope of the given equation, -11 gives the rate of change of the function per unit increase in the independent variable x

Therefore, the elevation decreases, by (-)11 feet for each increase in time by one second

3) The y-intercept gives the initial elevation of the balloon at time t = 0 seconds

The x-intercept gives the final elevation of the balloon when it lands at time t = 30 seconds

8 0

2 years ago

Read 2 more answers