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4 years ago

Can somebody please help me. I don’t understand it at all.

Mathematics

2 answers:

Aliun [14]4 years ago

7 0

You first make a table with x and y

like this: x | y

then you think of possible values for x then solve for y

it needs to be positive , 0, and a negative like:

under x, you do:

-3

then you take the equation and solve for y.

after, with the y values, create a Cartesian plane and plot the points

so the points would be (2,7), (0,5), and (-3,2)

then you connect the points and draw arrows on both ends.

then label the line w/ the equation

-------------------------------------------------------

hey btw, i learned this just yesterday. lol

great timing

lianna [129]4 years ago

4 0

Step-by-step explanation:

Just pick a bunch of values of x, and use the formula to find the corresponding value of y.

For example

When x = 0, y = 0+5 = 5 ----> Plot the point (0,5) on graph paper

When x = 1, y = 1+5 = 6 ----> Plot the point (1,6) on graph paper

When x = 2, y = 2+5 = 7 ----> Plot the point (2,7) on graph paper

Then connect the dots to get a linear graph. You should get a graph that looks like the one attached.

You might be interested in

Simplify the expression: 3x2⋅x2= a 3x b 3x4 c 3x2+2

DedPeter [7]

Answer:

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4. 24 can also be written as 4 × 6 and √4 = 2. So x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3. x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3. x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4. 88 can also be written as 4 × 22 and √4 = 2. So x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4. x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6. x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4. x = 9 ± √33 / 4 .

Step-by-step explanation:

8 0

3 years ago

Quadrilateral ABCD is located at A(−2, 2), B(−2, 4), C(2, 4), and D(2, 2). The quadrilateral is then transformed using the rule

kap26 [50]

For each point, add 7 to the x coordinate and take away 1 from the y-coordinate.

I am using a "tick-mark" to show the corresponding point, after "translation" (movement in a straight line). 

A(-2, 2) becomes A'(5, 1) 

Because all points have been translated in a straight line, in the same direction (the direction [7 -1]) by the same distance, the new figure A'B'C'D' will have the same shape, same size and same orientation as the original image. 

It will simply be in a different location on the graph. 

If you were to join A with A', B with B', and so on, you would see that all 4 vectors are parallel and are of equal length. 

If you were to compare the segment AB (side AB of the original quadrilateral) with the segment A'B' (in the new quadrilateral), you would see that they are parallel (same slope) and have the same length. 
Same with the other sides. 

Tow figures that are identical (except for their location) are said to be "congruent". 

--- 

The new rectangle will be far to the right (7 units in x) and a bit below (-1 in y) from the old one. 

You should draw the two figures on a graph, and you will see a lot of this very clearly.

8 0

3 years ago

Read 2 more answers

Graph the solution on the number line |x-3| <5

Anettt [7]

Answer:

-2<x<8

see below for graph

Step-by-step explanation:

First, we need to solve the inequality.

Inequality: |x-3|<5

Split into two equations:

x-3<5

x-3>-5 (notice how the sign is flipped when we make the number negative)

let's start with x-3<5

add 3 to both sides

x<8

now

x-3>-5

add 3 to both sides

x>-2

The graph is below

the intersection is the solution.

Notice how I made the maroon line go to the right- which shows that it's greater than (for x>-2) and the silver line go to the left, which shows that it's less than (for x<8)

the equation is -2<x<8

Hope this helps!