Rodney is starting a tutoring business.

Mathematics

1 answer:

sweet-ann [11.9K]2 years ago

7 0

Answer:

(a) 20 + 14(s)

(b)$146

Step-by-step explanation:

Use s as your variable per session.

$20 is a flat fee as a sign up for tutoring.

Therefore, 20 + 14s is the expression.

(b) 14x9=126 + 20 = 146

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3. A postal carrier can

Delicious77 [7]

Answer:

6 hours. ( I DID IT USING PROPORTIONS!)

Step-by-step explanation:

houses/hours

130/2.5= 312/x

(cross multiply)

130x = 780

130x/130 = 780/ 130 (divide each by 130)

6 = h

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3 years ago

Read 2 more answers

At 3 p.m. an oil tanker traveling west in the ocean at 14 kilometers per hour passes the same spot as a luxury liner that arrive

schepotkina [342]

<span>N(t) = 16t ; Distance north of spot at time t for the liner. W(t) = 14(t-1); Distance west of spot at time t for the tanker. d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t. Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is N(t) = 16t Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is W(t) = 14(t-1) The distance between the 2 ships is easy. Just use the pythagorean theorem. So d(t) = sqrt(N(t)^2 + W(t)^2) If you want the function for d() to be expanded, just substitute the other functions, so d(t) = sqrt((16t)^2 + (14(t-1))^2) d(t) = sqrt(256t^2 + (14t-14)^2) d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) ) d(t) = sqrt(452t^2 - 392t + 196)</span>

3 0

3 years ago

2y+18=42 what is y, and how would you find it?

Nesterboy [21]

Answer:

y=12

Step-by-step explanation:

Use order of operations. Subtract 18 from both sides and the divide by 2.

2y+18 -18=42-18

2y=24

y=12

3 0