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vovangra [49]
3 years ago
6

A shipment of ball bearings with a mean diameter of 25 mm and a standard deviation of 0.2 mm is normally distributed. By how man

y standard deviations does a ball bearing with a diameter of 25.6 mm differ from the mean?
Mathematics
1 answer:
LiRa [457]3 years ago
4 0
The choices for this question can be found elsewhere and as follows:

0.6
1
2
<span>3
</span>
We calculate as follows:

Mean = 25 mm
Standard Deviation = 0.2 mm
Value = 25.6 mm

25.6 - 25 = .6 mm
.6 mm / 0.2 mm = 3

Therefore, the correct answer is the last option, 3.

<span />
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What is the image of (-6, -2) after a dilation by a scale factor of 4 centered at the origin?​
Leviafan [203]

Answer:  (-24, -8)

Explanation: Multiply the coordinates of the given point by the scale factor 4. This only works if the center of dilation is the origin.

6 0
2 years ago
Meg is a veterinarian. In a given week, 50% of
krek1111 [17]

Answer:

<u><em></em></u>

  • <u><em>a. Meg needs to find the part</em></u>

<u><em></em></u>

  • <u><em>b. Steve needs to find the percent.</em></u>

<u><em></em></u>

Step-by-step explanation:

The question is incomplete.

This is the complete question:

<em>Meg is a veterinarian. In a given week, 50% of the 16 dogs she saw were Boxers. Steve is also a veterinarian. In the same week, 7 of the 35 dogs he saw this week were Boxers. Each wants to record the part the whole, and the percent.</em>

<em />

<em>a. Does Meg need to find the part, the whole, or the percent.</em>

<em />

<em>b. Does Steve need to find the part, the whole, or the percent.</em>

<em />

<h2>Solution to the problem</h2>

<u><em>a. Does Meg need to find the part, the whole, or the percent.</em></u>

<em />

<em>Meg</em> already knows the <em>whole</em> and the <em>percent</em>.

The whole is the entire number of dogs seen: <em>16 dog</em>s.

The percent is <em>50%.</em>

Hence, she needs to find the part: this is how many (what part) of the 16 dogs she saw were boxers.

And she can do with a simple operation:

  • Part = whole × percent = 16 × 50% = 8. This is 8 dogs of 16 were boxers.

<u>b. Does Steve need to find the part, the whole, or the percent.</u>

<u></u>

He already knows <em>the part</em> (<em>7 of the 35 dogs were boxers</em>) and <em>the whole </em>(<em>35 dogs</em>).

Then he needs to find the percent, which he can do using the next operation:

  • Percent = (part / whole) × 100 = (7/35)×100 = 20%
6 0
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8 0
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rodikova [14]

Answer:

53

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48 in+ 5 in= 53

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An article valued $120 was increased by 12%. determine the new value
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