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Rzqust [24]
3 years ago
8

caffeine takes a certain amount of time to leave your system if you drink 3 cups of coffee in the morning, the function that rep

resents the amount of caffeine remaining in your body after drinking the coffee is given by (gt)=130(.8346) where is t time in hours.
Mathematics
2 answers:
k0ka [10]3 years ago
6 0

Answer:

3

Step-by-step explanation:

Gwar [14]3 years ago
3 0

Answer:

What's the question you're asking im very confused of what you're trying to ask

Step-by-step explanation:

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The ratio of boys to girls in a class is 4 to 5. There are 20 boys in the class. How many girls are in the class
skelet666 [1.2K]

There would be 25 girls. You would turn it into a fraction and times both by 5 to get 20/25. 5/4=1.25 and 25/20=1.25 in case you need to check your work

8 0
3 years ago
Answer this question to get marked as brainliest!!!!!
____ [38]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Write the x-intercept of the graph of -6x + y = 8.
Trava [24]

Answer:

x-intercept:  x = -4/3

Step-by-step explanation:

x-intercept when y = 0

-6x + 0 = 8

so

-6x = 8

x = 8/-6

x = -4/3

6 0
4 years ago
Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From
maksim [4K]

Answer:

The 95% CI for the difference of means is:

-155.45 \leq \mu_1-\mu_2 \leq -44.55

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."</em>

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size:  4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

M_d=M_1-M_2=200-300=-100

The standard deviation can be estimated as:

\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45

The degrees of freedom are:

df=n_1+n_2-2=10+4-2=12

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55

8 0
3 years ago
Help please I beg you I’m stressed out
Dominik [7]
1.)18/27 2.)15:10 3.)6.30 4.)160 5.)400 6.)426 7.)10 cups 8.)102.4 9.)0 1
3 0
4 years ago
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