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3 years ago

find the value of" A" such that triangle DEF with vertices D (a,1) , E(10,7) and F(7 ,11) is a right angle at E?

Mathematics

1 answer:

Ronch [10]3 years ago

4 0

a=2

Answer:

(m1) slope of DE=(7-1)/(10-a)=6/(10-a)

(m2) slope of EF=(11-7)/(7-10)=4/-3=-4/3

since line are perpendicular

m1m2=-1

6/(10-a) ×-4/3=-1

6/(10-a)=3/4

6×4=3(10-a)

24=30-3a

3a=30-24

a=6/3=2

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3 years ago

Find the annual rate of interest. Principal = 4600 rupees Period = 5 years Total amount = 6440 rupees Annual rate of interest =

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Answer:

The rate of interest for compounded annually is 6.96 % .

Step-by-step explanation:

Given as :

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<u>From compounded method</u>

Amount = Principal × $(1+\dfrac{\textrm rate}{100})^{\textrm Time}$

or, Rs 6440 = Rs 4600 × $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

Or, $\frac{6440}{4600}$ = $(1+\dfrac{\textrm R}{100})^{\textrm 5}$

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2 years ago

find the value of" A" such that triangle DEF with vertices D (a,1) , E(10,7) and F(7 ,11) is a right angle at E?​

find the value of" A" such that triangle DEF with vertices D (a,1) , E(10,7) and F(7 ,11) is a right angle at E?