Answer:
sorry bro sorry sorry sorry sorry sorry sorry
Answer:
x=-27, y=-15
Step-by-step explanation:
In the attached file
I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
$9,812.29
Step-by-step explanation:
The amount in Jeremy's account can be computed using the compound interest formula.
__
<h3>account value</h3>
The formula for the value of an account earning compound interest at annual rate r, compounded n times per year for t years is ...
A = P(1 +r/n)^(nt)
where P is the principal invested.
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<h3>formula application</h3>
When P=$8500, r=0.024, n=4, t=6, the formula becomes ...
A = $8500(1 +0.024/4)^(4·6) = $8500(1.006^24) ≈ $9812.29
There will be $9,812.29 in this account after 6 years.
