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2 years ago

3+m+4≤5 please help due tommorow

Mathematics

2 answers:

ruslelena [56]2 years ago

7 0

$3+m+4 \leq 5 \\\\ m+7 \leq 5 \\\\ m \leq 5-7 \\\\ m \leq -2 \\\\ \boxed{m=(-\infty;-2]}$

algol [13]2 years ago

7 0

3+m+4≤5
m+7≤5
m+7-7≤5-7 (you have to subtract 7 on both sides)
m≤-2

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Problem We can calculate EEE, the amount of euros that has the same value as DDD U.S. Dollars, using the equation E=\dfrac{17}{2

Tanzania [10]

Complete Question

We can calculate EEE, the amount of euros that has the same value as DDD U.S. Dollars, using the equation

E= 17/20 D

a) How many euros have the same value as 1 U.S. Dollar? euros

b) How many U.S. Dollars have the same value as 1 euro? dollars

Answer:

a) 0.85 euros

b) 1.18 dollars

Step-by-step explanation:

The equation is given as:

E= 17/20 D

a) How many euros have the same value as 1 U.S. Dollar? euros

E = 17/20D

D = 1 dollar

Hence:

E = 17/20 × 1

E = 0.85 euros

b) How many U.S. Dollars have the same value as 1 euro? dollars

E = 17/20D

E = 1 euro

1 = 17/20D

D = 1 ÷ 17/20

D = 1 × 20/17

D = 1.1764705882 dollars

D = 1.18 dollars

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2 years ago

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The answer is 30, hope this helps.

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Stacy sells art prints for $12 each. Her expenses are $2.50 per print, plus $38 for equipment. How many prints must she sell for

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Answer:

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22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

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= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

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A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

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Step-by-step explanation:

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