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3 years ago

3+m+4≤5 please help due tommorow

Mathematics

2 answers:

ruslelena [56]3 years ago

7 0

$3+m+4 \leq 5 \\\\ m+7 \leq 5 \\\\ m \leq 5-7 \\\\ m \leq -2 \\\\ \boxed{m=(-\infty;-2]}$

algol [13]3 years ago

7 0

3+m+4≤5
m+7≤5
m+7-7≤5-7 (you have to subtract 7 on both sides)
m≤-2

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Answer the following please give steps of how you got your answer

konstantin123 [22]

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Step-by-step explanation:

1. Rewrite the expression in fraction form:

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2 years ago

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Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
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Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

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2 years ago