We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
50,000 is the answer because if you multiply 5,000 and 10 you get 50,000. And if you divide 50,000 by 10 you get 5,000. Which is 1/10 of 50,000.
The answer is 1/(x+4)
Explanation:
You would factor out the denominator
So,
(X-4)(x+4)=x^2-16
So, x-4/(x+4)(x-4)
Then x-4 cancels each other out from the numerator and denominator
Leaving 1/x+4
Answer: 33
Step-by-step explanation: substitute a with 22 and c with 11.
22+11=33
