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3 years ago

A father is 32 years older than his son. In four years,

Mathematics

1 answer:

sergiy2304 [10]3 years ago

5 0

Answer:

father: 36
son: 4

Step-by-step explanation:

Let s represent the son's age now. Then s+32 is the father's age. In 4 years, we have ...

5(s+4) = (s+32)+4

5s +20 = s +36 . . . . . eliminate parentheses

4s = 16 . . . . . . . . . . . . subtract s+20

s = 4

The son is now 4 years old; the father, 36.

_____

<em>Alternate solution</em>

In 4 years, the ratio of ages is ...

father : son = 5 : 1

The difference of their ages at that time is 5-1 = 4 "ratio units". Since the difference in ages is 32 years, each ratio unit must stand for 32/4 = 8 years. That is, the future age ratio is ...

father : son = 40 : 8

So, now (4 years earlier), the ages must be ...

father: 36; son: 4.

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