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Alekssandra [29.7K]
3 years ago
8

A line passes through (2, -1) and (8, 4).

Mathematics
1 answer:
german3 years ago
7 0
Slope of the line = (4--1) / (8-2)  = 5/6

point slope form is  y-y1 = m(x-x1)  where m=slope and (x1,y1) is a point on the line 
so the answer to (a) is    y + 1 = (5/6)(x - 2)  Answer

(b)  multiply the above equation by 6:-

6y + 6  = 5(x - 2)

6y + 6 = 5x - 10

5x - 6y  = 16    is the equation in standard form  Answer

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24 inches. You could simply multiply by 2. Do you want another solution?


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The slope is negative as it slopes to the left
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Express the fractions 1/2, 3/16, and 7/8 with an LCD. A. 1/4, 3/4, and 7/4 B. 8/16, 3/16, and 14/16 C. 1/32, 3/32, and 7/32 D. 4
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B. 8/16, 3/16, and 14/16
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PLEASEEE I DONT KNOW HOW TO DO ITTTT. THE 35.8 IS RIGHT BUT I CANT GET MEASURE OF ANGLE C AND A I GOT 46.2 for A AND 70.8 for C
Rashid [163]

Answer:

Hope it helps....!!!!!

Step-by-step explanation:

AB = c = 38

BC = a = 29

AC = b

Angle ABC = 63 degrees

Solving for AC   "b":

Cosine rule: c^2 = a^2 * b^2 -2ab * cos C

38^2 = 29^2 * b^2 - (2* 29) * b * (cos 38)

1444 = 841 * b^2 - 58 * b * 0.955

(1444 + 58)/0.955 = b^2 * b

1572.77486911 = b^3

11.62935 = b

11.63 = b (rounded to two decimal places)

Now solving for angle A:

Sine rule: a/sinA = b/sinB

29/sinA = 11.63/sin(63)

sinA/29 = sin(63)/11.63

sin A = (sin(63)/11.63) * 29

sin A = 0.41731

A = sin^-1 (0.41731)

A = 24 degrees 39 minutes 53 seconds

Now solving for angle C:

Sine rule: c/sinC = b/sinB

38/sinC = 11.63/sin(63)

sinC/38 = sin(63)/11.63

sin C = (sin(63)/11.63) * 38

sin C = 0.54682

C = sin^-1 (0.54682)

C = 33 degrees 8 minutes 56 seconds

3 0
3 years ago
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