Answer:
t = 9.7 seconds
Step-by-step explanation:
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation as :

We need to find the time that the rocket will hit the ground, to the nearest 100th of second.
When the rocket hit the ground, So,

Neglecting negative tim,
t = 9.7 s
Hence, it will hit the ground at 9.7 seconds.
Is there a photo? I can’t answer the question without the question.
The value of x and y is 5 , 7
<h3>What is an Equation ?</h3>
An expression consists of variables , constants and mathematical operators , when equated by any other algebraic expression or a constant it becomes an equation.
The equation given in the question is
(x + 1)/2 -(y+4)/11 = 2
(x+3) /2 + (2y+3)/17 = 5
It has to be solved for x and y ,
The simplification of the equation has to be done
and the equation is
11x-2y = 41 -----------1
and
17x +4y = 113 -------------------2
to find the solution elimination method will be followed as
Multiplying equation 1 by 2 and adding the both equations
39x = 195
x = 5
Substituting this value in equation 1
55 -2y = 41
y = 7
The value of x and y is 5 , 7
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Answer:5x
Step-by-step explanation: