Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
P is 5 ticks to the left of 0, so it would be -5/8
Q is 5 ticks to the right of 0, so it would be at 5/8
an absolute value turns a negative number into a positive number
so absolute value of P located at -5/8 = 5/8
this is the location of point Q
<span>Jimmy said that the absolute values of the numbers represented by the two points are the same.
</span>
so Jimmy is correct
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Answer:
Step-by-step explanation: