-4(x+10)-6=-3(x-2)
-4x-40-6=-3x+6
-4x-46=-3x+6
-4x-46+46=-3x+6+46
-4x=-3x+52
-4x+3x=-3x+3x+52
-x=52
(-x/-1)=(52/-1)
x=-52
Answer:εδΑΒΓΒΕ
![U4\leq \sqrt{x} \sqrt[n]{x} 64](https://tex.z-dn.net/?f=U4%5Cleq%20%5Csqrt%7Bx%7D%20%5Csqrt%5Bn%5D%7Bx%7D%2064)
Step-by-step explanation:
73hsay is a little bit too long and ∩679∨78ω8㏒∴≠÷±
Answer:
It represents an infinite cylinder of radius 4.
Step-by-step explanation:
The first thing to notice is that

<u>represents a circle of radius 4</u>, with its center in the origin of a plane yz, of cartesians coordinates.
Starting from here, we have to put the coordinate x, for all values of x, to complete the space R³. <em>This will enlarge this circle we had on the plane, to infinity</em> (positive and negative on the x-axis).
Finally, we have that this region is a cylinder of radius 4, with center in y=0 and z=0, and of infinite length in the x coordinates.
horizontal shift: 3 units to the left
vertical shift: 4 units down
We have to solve this quadratic equation
for n to get <em>which figure has 56 blocks</em>.

For middle term factorization, we need <em>two numbers that multiplied gives us -56 and added gives us 1 (coefficient of n).</em>
<em>Such two numbers are </em><em>8</em><em> and </em><em>-7</em><em>. We can now write,</em>
<em>
</em>
<u><em>"There is no negative figure number possible, so we disregard -8"</em></u>
Our answer is 7.
ANSWER: The 7th figure has 56 blocks.