C
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Answer: Choice C
![\left[0 , \frac{\pi}{2}\right) \ \ \text{ and } \ \ \left(\frac{\pi}{2}, \pi\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%20%2C%20%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%29%20%5C%20%5C%20%5Ctext%7B%20and%20%7D%20%5C%20%5C%20%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cpi%5Cright%5D)
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Explanation:
Let's look at the function y = sec(x) first, which is the secant function.
Recall that secant is 1 over cosine, so sec(x) = 1/cos(x)
We can't divide by zero, so cos(x) = 0 can't be allowed. If x = pi/2, then cos(pi/2) = 0 will happen. So we must exclude pi/2 from the domain of sec(x).
If we look at the interval from 0 to pi, then the domain of sec(x) is 
we can condense that into the interval notation ![\left[0 , \frac{\pi}{2}\right) \ \ \text{ and } \ \ \left(\frac{\pi}{2}, \pi\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%20%2C%20%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%29%20%5C%20%5C%20%5Ctext%7B%20and%20%7D%20%5C%20%5C%20%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cpi%5Cright%5D)
Note the use of curved parenthesis to exclude the endpoint; while the square bracket includes the endpoint.
So effectively we just poked at hole at x = pi/2 to kick that out of the domain. I'm only focusing on the interval from 0 to pi so that secant is one to one on this interval. That way we can apply the inverse. When we apply the inverse, the domain and range swap places. So the range of arcsecant, or
is going to also be ![\left[0 , \frac{\pi}{2}\right) \ \ \text{ and } \ \ \left(\frac{\pi}{2}, \pi\right]](https://tex.z-dn.net/?f=%5Cleft%5B0%20%2C%20%5Cfrac%7B%5Cpi%7D%7B2%7D%5Cright%29%20%5C%20%5C%20%5Ctext%7B%20and%20%7D%20%5C%20%5C%20%5Cleft%28%5Cfrac%7B%5Cpi%7D%7B2%7D%2C%20%5Cpi%5Cright%5D)
Yes it can be a direct variation. it follows the form y = kx
The only variable that cannot be held constant is F, but we can hold the mass constant and vary the acceleration OR we can hold the acceleration constant and vary the mass. Either one would work, but the easiest would be to vary the mass and hold the acceleration constant since we are all pulled by the same action gravity
Answer:
∠DCE≅∠BAE
Step-by-step explanation:
CPCTC is basically used at or near the end of a proof which asks the student to show that two angles or two sides are congruent. Corresponding means they're in the same position in the 2 triangles
two side CE and AE are equivillant in the expression
hence
∠DCE≅∠BAE is right option.
The sugar mill production had increased (blank) times this year since it began. The sugar mill's production increases exponentially by the rate of growth or the base of the exponent in the formula.