All categories

3 years ago

Complete the equation of the line whose slope is -2 and y-intercept is (0,3)(

Mathematics

1 answer:

kow [346]3 years ago

4 0

Answer: y=-2x+3

Step-by-step explanation:

You have to make a linear equation, which is in the y=mx+b format

m, which stand for slope is given. m=-2

b, which stand for the y-intercept, is also given. b=3

Therefore: y=-2x+3

You might be interested in

Use the quadratic formula to find the solutions for.. y = 2x^2 - 9x + 5.

Yakvenalex [24]

Answer: $x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

Step-by-step explanation:

$2x^2-9x+5$

a=2

b=-9

c=5

$x=\frac{-b\frac{+}{}\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-9)\frac{+}{}\sqrt{(-9)^2-4(2)(5)} }{2(2)}$

$x=\frac{9\frac{+}{}\sqrt{81-40} }{4}$

$x=\frac{9\frac{+}{}\sqrt{41} }{4}$

$x=\frac{9}{4}-\frac{\sqrt{41} }{4} \\x=\frac{9}{4}+\frac{\sqrt{41} }{4}$

4 0

3 years ago

Write the product using exponents. 1/5 x 1/5 x 1/5 x 1/5 x 1/5

damaskus [11]

Answer: 1/5 with an exponent of 5.

hope this helps :)

7 0

2 years ago

Write the name of the period that has the digits 913.

sergejj [24]

The name of period that has the digits 913 is hundreds.
Because Period is considered to a group of places of the digits.

In this case, the given number is 913 and it is the group of hundred because 900 is the highest number it contains.

We can also write 913 as

913 = 900 + 10 + 3

It means,

9 hundreds + 10 tens + 3 ones

8 0

3 years ago

Josh lives one for 6 miles from the park so far he walked 2/3 of the distance from his house to the park how many miles has josh

Naily [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss

mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

$\frac{ad+cb}{bd}$ ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

$\frac{a}{b}+\frac{c}{d}$

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

$\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{ad+cb}{bd}$

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

$\frac{ad+cb}{bd}$ ∵ b≠0, d≠0, so bd≠0

3 0

3 years ago