The coordinate of the vertex is; (h, k) = (3, -5)
The final equation of the parabola is; y = 5(x - 3)² - 5
<h3>How to find the vertex of a Parabola?</h3>
The vertex is the coordinate of the crest or trough of the curve. Now, in the given graph, we only have a Trough which is the lowest point of the graph.
The coordinate of the vertex is; (h, k) = (3, -5)
2) Since the general equation is;
y = a(x - h)² + k
We will have;
y = a(x - 3)² - 5
At x = 2, y = 0. Thus;
0 = a(2 - 3)² - 5
a - 5 = 0
a = 5
3) The final equation of the parabola is;
y = 5(x - 3)² - 5
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Answer:
- asymptotes: x = -4, x = 4
- zeros: x = 0
Step-by-step explanation:
The vertical asymptotes of the rational expression are the places where the denominator is zero:
x^2 -16 = 0
(x -4)(x +4) = 0 . . . . . true for x=4, x=-4
x = 4, x = -4 are the equations of the vertical asymptotes
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The zeros of a rational expression are the places where the numerator is zero:
4x = 0
x = 0 . . . . . . divide by 4
Answer:
y = 90
Step-by-step explanation:
You can use proportions to answer this question.

Cross multiply 30 to -9; -3 to y

Isolate <em>y</em> by dividing -3 on both sides

Answer:
y=4x-1
Step-by-step explanation:
Remember the point slope form equation y-y1=m(x-x1) where m is the slope and the given point is (x1,y1)
y-7=4(x-2) . Plug in the numbers for the equation
y-7=4x-8 distributive property
y = 4x-1