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Mandarinka [93]

2 years ago

5

Dennis has 14 skittles. If Dennis gave equal numbers of skittles to his 8 friends and then ate what was left, how many skittles

did each person eat?

1 answer:

lara [203]2 years ago

4 0

Answer:

1.75

Step-by-step explanation:

Just divide 14 by 8 and you get your answer !!!!

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What is the volume of a sphere with a surface area of 452.39cm^2? Round to the nearest hundredth.

horrorfan [7]

The answer is 904.78cm³ Hope I helped, please rate brainliest.

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3 years ago

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The ordered pairs show (height in inches, men’s shoe size). (70, 9.5) (67, 8) (69, 9) (72, 11.5) (68, 7.5) (60, 6) (71, 11) Use

erma4kov [3.2K]

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2 years ago

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When will these two lines intersect <br>C. y=-2x +3<br>y = x

Andrej [43]

Answer:

The intersection point of the given lines is (1,1).

Step-by-step explanation:

Here, the given equations are:

y = - 2 x + 3

y = x

Substitute y = x in the first equation,

y = -2 x + 3 becomes y = -2 (y) + 3

or, y + 2 y = 3

or, 3 y = 3 ⇒ y = 3/3 = 1

⇒ y = 1

Now, as x = y ⇒ x = 1

Hence, the intersection points of the given lines is (1,1).

8 0

2 years ago

Y = 8x + 6, x = 5 plz help i can get admin if i solve this

RoseWind [281]

Answer:

y = 46

Step-by-step explanation:

I'm assuming you wanted to solve for y.

x = 5

y = 8(5) + 6

y = 40 +6

y = 46

8 0

2 years ago

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

3 0

2 years ago