The newly-discovered organism Yawle nhoj, has a diploid chromosome number of 56. Suppose that one of the chromosome pairs fails
to disjoin properly during Meiosis I. How many chromosomes will be present in each of the four gametes that result from that meiosis? Assume meiosis II is normal.
The correct answer will be 2 gametes with 29 chromosomes and 2 gametes with 27 chromosomes will be formed.
Explanation:
Meiosis is a type of cell division which produces four daughter cells. Chromosomes separate or the disjunction of chromosomes takes place during anaphase I and anaphase II of meiosis I and II respectively.
If a chromosome fails to disjoin at meiosis I this will result in the production of four gametes with an unequal number of chromosomes. Out of four gametes, 2 gametes produced will be trisomic gametes that are with one additional copy of chromosome and 2 gametes will be monosomic with one less number of chromosome. It means the trisomic gametes will have 29 chromosomes while 2 monosomic gametes will have 27 chromosomes.
Thus, 2 gametes with 29 chromosomes and 2 gametes with 27 chromosomes will be formed is the correct answer.
