To make h subject of the formula, the other expressions in the equation is expressed to equal h as follows:
- h = (1 + E + 0.5π√x/)(π√x + 1 + E)
<h3>How can h in the equation,
![E = 1-\pi \sqrt{x} (\frac {h-0.5}{1-h})](https://tex.z-dn.net/?f=E%20%3D%201-%5Cpi%20%5Csqrt%7Bx%7D%20%28%5Cfrac%20%7Bh-0.5%7D%7B1-h%7D%29)
be made subject of the formula?</h3>
The steps in making h subject of the formula in the given equation are as follows:
Step 1: Add
to both sides
![E + \pi \sqrt{x} (\frac {h-0.5}{1-h})= 1](https://tex.z-dn.net/?f=E%20%2B%20%5Cpi%20%5Csqrt%7Bx%7D%20%28%5Cfrac%20%7Bh-0.5%7D%7B1-h%7D%29%3D%201)
Step 2: subtract E from both sides
![\pi \sqrt{x} (\frac {h-0.5}{1-h}) = 1 + E](https://tex.z-dn.net/?f=%5Cpi%20%5Csqrt%7Bx%7D%20%28%5Cfrac%20%7Bh-0.5%7D%7B1-h%7D%29%20%3D%201%20%2B%20E)
Step 3: divide both sides by π√x
h - 0.5/1 - h = 1 + E/π√x
Step 4: cross multiply
(h - 0.5)(π√x) = (1 + E)(1 - h)
hπ√x -0.5π√x = 1 - h + E - hE
Step 5: collect like terms
hπ√x + h + hE = 1 + E + 0.5π√x
h(π√x + 1 + E) = 1 + E + 0.5π√x
Step 6: divide both sides by (π√x + 1 + E)
h = (1 + E + 0.5π√x/)(π√x + 1 + E)
In conclusion, in making h subject of the formula, the other expressions in the equation is expressed to equal h.
Learn more about subject of the formula at: brainly.com/question/657646
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