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Julli [10]
3 years ago
10

Write the standard form of the line that passes through the given points (6,1) and (5,4)

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

The standard form:

Ax+By=C

The point-slope form:

y-y_1=m(x-x_1)

m - slope

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (6, 1) and (5, 4). Substitute:

m=\dfrac{4-1}{5-6}=\dfrac{3}{-1}=-3

y-1=-3(x-1)      <em>use distributive property</em>

y-1=-3x+3          <em>add 1 to both sides</em>

y=-3x+4         <em>add 3x to both sides</em>

\boxed{3x+y=4}

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In the diagram, Ray K QJKM is a straight angle.
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The true statements about the diagram given are:

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<h3>What is an Angle Bisector?</h3>

An angle bisector is a segment that divides a given angle into two parts that are congruent to each other.

The missing part of the question is in the image attached below.

In the image given, PK bisects the straight angle JKM since angles JKP and MKP both equal 90 degrees (right angle).

Therefore, m∠JKL = m∠PKL = 45°

m∠MKQ + m∠PKQ = m∠PKM based on the angle addition theorem.

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(see image attached below)

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