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Julli [10]
3 years ago
10

Write the standard form of the line that passes through the given points (6,1) and (5,4)

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

The standard form:

Ax+By=C

The point-slope form:

y-y_1=m(x-x_1)

m - slope

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (6, 1) and (5, 4). Substitute:

m=\dfrac{4-1}{5-6}=\dfrac{3}{-1}=-3

y-1=-3(x-1)      <em>use distributive property</em>

y-1=-3x+3          <em>add 1 to both sides</em>

y=-3x+4         <em>add 3x to both sides</em>

\boxed{3x+y=4}

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Answer:

m = {-6, -4}

Step-by-step explanation:

<u><em>Subproblem 1:</em></u>

Set the factor '(6 + m)' equal to zero and attempt to solve:

Simplifying

6 + m = 0

Solving

6 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-6' to each side of the equation.

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0 + m = 0 + -6

m = 0 + -6

Combine like terms: 0 + -6 = -6

m = -6

Simplifying

m = -6

<u><em>Subproblem 2:</em></u>

Set the factor '(4 + m)' equal to zero and attempt to solve:

Simplifying

4 + m = 0

Solving

4 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + m = 0 + -4

Combine like terms: 4 + -4 = 0

0 + m = 0 + -4

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