I'm going to assume that you're asking for the<em> equation</em> of that circle.
It's
<u>(x + 4)² + (y - 3)² = 16</u>
In the problem, we are given that the probability of getting
a bear is equal to p. Where probability is the share of successful outcome in
this case is the bear) over total outcomes (total amount of prizes).
The likelihood of not receiving a bear two times in a row is
containing of 2 tries:
try 1: 1st spin gets a bear, 2nd spin does not receive a
bear
total probability of try 1 = p * (1 – p)
try 2: 1st spin does not get a bear, 2nd spin gets a
bear
total probability of try 1 = (1 – p) * p
The total probability of the 2 tries is just the sum of
the 2:
Overall probability of not getting a bear twice in a row= p
* (1 – p) + (1 – p) * p
Simplifying this will give us:
Overall probability of not getting a bear twice in a row =
2p * (1 – p)
Therefore, the likelihood of not receiving a bear twice in a
row > 3 times the probability of getting the teddy bear. Rewriting the
statement, will give us the inequality of 2p * (1 – p) > 3 p
<span> </span>
No.
An integer is a whole number.
In the case of .634 (or 0.634), we see that it is not a whole number, as there is a decimal point, and numbers to the right of the decimal points.
hope this helps
Answer:x=7
Step-by-step explanation:
X+3=10
-3 -3
X=7
Answer:
(0,3) and (1,4) are solution sets of given system
Step-by-step explanation:
Given that:
y= 3x^2−2x+3 ------------- eqA
y = x + 3 ------------------ eqB
Putting value of y from eqB to eqA
x + 3 = 3x^2−2x+3
Taking all variables to left side:
Signs pf transferred terms will be changed
3x^2−2x+3 - x - 3 = 0
Adding like terms we get:
3x^2−3x = 0
Dividing both sides by 3 we get:
x^2 - x = 0
Now take x common:
x(x-1)= 0
So
x = 0 and x = 1
Now put value in eqB
y = 0 + 3 and y= 1 + 3
we get:
y = 3 and y = 4
So solution sets are:
(0,3) and (1,4)
i hope it will help you!