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pishuonlain [190]
3 years ago
7

From the Mean Value Theorem for Integrals, we know that there is a c in (3,4) such that ????(c) equals this average value you ju

st found. Find c. g
Mathematics
1 answer:
kumpel [21]3 years ago
4 0

Answer:

1)a

2)c=f'(c)\\f'(c)=\int_{4}^{3}f'(x)dx

Step-by-step explanation:

Despite some missing part like the function, still we can affirm:

1) The <em>Mean Value Theorem</em> states that given a differentiable function <em>f</em> over an interval (a, b) [in this case (3,4)], then we know that there's a value "c" of between the endpoints of this interval.

And this c:

a

2) If c equals to the average value, then we can say that:

c=f'(c)

And

f'(c)=\frac{1}{4-3}\int_{4}^{3}\frac{f'(x)}{4-3}dx\Rightarrow f'(c)=\int_{4}^{3}f'(x)dx

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