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wolverine [178]
3 years ago
8

My little sister needs help 2(4x-1)=?

Mathematics
2 answers:
Vsevolod [243]3 years ago
6 0

Answer:

8x-2, or \frac{1}{4} if you meant it with a zero at the end

Step-by-step explanation:

When a factor is outside the parentheses, multiply what is inside it by the factor in front!

2(4x-1)=2*4x+2*-1=8x-2

Or if you meant it with a 0 at the end,

8x-2=0\\8x=2\\x=\frac{2}{8}\\ x=\frac{1}{4}

Hope this helps!

P.S. Hi little Sis! Hope you get better at math!

zepelin [54]3 years ago
3 0

Answer:

Step-by-step explanation:

8x-2

8x=-2

/8

x=-1/4

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Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

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Finger [1]

Answer:

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Step-by-step explanation:

5/8 + 3/4

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5 0
3 years ago
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Answer:

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Step-by-step explanation:

We are given an equation of inequality of single variable x.

So, we have to solve the inequality and get the solution in terms of another inequality.

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{Dividing both sides of an inequality with a positive number need no change in inequality sign}

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Answer:

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3 years ago
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