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Ludmilka [50]
3 years ago
11

I have 7 different calculus textbooks and 4 different number theory text books. In how many ways can I place the 11 text books o

n a bookshelf, in a row, if there must be a number theory text book in the middle, and there must be a calculus textbook at each end.
Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0

There are 7 ways to choose the calculus textbook at one end, then 6 ways to choose the calculus textbook at the other end.  Then there are 9 ways to choose the second textbook, 8 ways to choose the third textbook, and so on.  But then there are 4 ways to choose the number theory textbook, so there are 7*6*9!*4 = 60963840 ways that work.

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MA_775_DIABLO [31]
First find the area of the triangle
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2 years ago
PPPLEASE HELP<br><br> do the problem
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Step-by-step explanation:

1. No: angles add to more than 180 deg.

2. Yes: each side's length is between the sum and difference of the lengths of the other two sides.

3. No: not every side's length is between the sum and difference of the lengths of the other two sides.

4. Yes: for example, place the 50 deg angle between the two given sides. Another side will then make the triangle.

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The total amount of money earned by all three plumbers on Monday was $1,400. On Tuesday they earned a total of $1,660, and on We
Alekssandra [29.7K]
Set of equations that can be used to calculate rate for each plumber:
2A+8B+8C = 1,400 --- (1)
4A+7B+10C = 1,660 --- (2)
3A+9B+9C = 1,660 --- (3)
------------------------------------
2*(1) - (2)
------------------------------------
4A+16B+16C = 2,800
4A+7B+10C = 1,660 -
------------------------------------
       9B+6C = 1,140 --- (4)
------------------------------------
3(2) -4(3)
-----------------------------------
12A+21B+30C = 4,980
12A+36B+36C = 6,600 -
-----------------------------------
         -15B-6C = -1,620 --- (5)
------------------------------------
(4) + (5)
------------------------------------
9B+6C = 1140
-15B-6C = -1620 +
-------------------------------------
-6B = -480 => 6B = 480 => B = 480/6 = 80
-------------------------------------------------------
Using (4), 9(80)+6C = 1140
720+6C = 1140 => 6C = 1140-720 = 420 => C = 420/6 = 70
------------------------------------------------------------------------------
Using (1), 2A+8(80)+8(70) = 1400
2A+640+560 =1400 => 2A = 1400-640-560 = 200 => A = 200/2 = 100
----------------------------------------------------------------------------------------------
The rates are:
A = $100
B = $80
C = $70
--------------------------------
On Thursday, number of calls: A = 4 hrs, B = 6 hrs, C = 3 hrs
Money earned = 4*100+6*80+3*70 = $1,090
6 0
3 years ago
Read 2 more answers
In one city, taxi company A charges $5 plus $0.35/km travelled. Taxi company B charges $3.50 plus $0.50/km.
lions [1.4K]

Answer:

If you are asking for the equations, Company A would be 0.35x + 5 and Company B would be 0.50x + 3.50. :)

Step-by-step explanation:

3 0
3 years ago
Please Help!
victus00 [196]
The GCF is 2
Pull out 2 from each number:
2(2n + 5)
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