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3 years ago

Mr. Smith is unhappy with the 2 foot concrete walkway around the edge of the pool. He decides to

1 answer:

5 0

Given that the total area of the walkway and the pool is w²+17w+66, and the width w, will be found as follows:
A=length×width
A=w²+17w+66
to get the new width we need to factorize the above quadratic form
A=w²+17w+66
=w²+11w+6w+66
=w(w+11)+6(w+11)
=(w+11)(w+6)
From the answer, the width=6 units, length=11 units

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Am i right or am i wrong

frutty [35]

Answer:

you're right

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3 years ago

Coco scored team player three games in weekend.They scored: •six points in the first game, •half as many points in the second g

dolphi86 [110]

Answer:

6/2+6+2

and the answer is 11

Step-by-step explanation:

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3 years ago

When a number is added to 1/5 of itself, the result is 24. The equation that models this problem is n +1/5 n = 24. What is the v

Lady_Fox [76]

For this case we must find the value of n of the following equation:

$n + \frac {1} {5} n = 24$

Taking common factor "n" from the left side of the equation we have:

$n (1+ \frac {1} {5}) = 24\\n \frac {6} {5} = 24$

Multiplying by 5 on both sides of the equation:

$6n = 120$

Dividing between 6 on both sides of the equation:

$n = 20$

Thus, the value of n is 20.

Answer:

$n = 20$

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3 years ago

Read 2 more answers

If 64 seedlings are allowed 24cm? of space ?<br> How much space should be allowed for 48 seedlings?

Monica [59]

128 cm square space is required for 48 seedlings

check

for 1 seedlings= 64÷ 24

= 2.66

for 48 seedlings = 2.66666667× 48 = 128

if right plz give Brainliest would really appreciate it.

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Be safe

Be healthy

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3 years ago

Suppose you have a 6-face unfair dice with numbers 1,2,3,4,5,6 on each of its faces. If the probability distribution of throwing

kotegsom [21]

Answer:

D is correct

Step-by-step explanation:

Here, we want to select which of the options is correct.

The correct option is the option D

Since the die is unfair, we expect that the probability of each of the numbers turning up

will not be equal.

However, we should also expect that if we add the chances of all the numbers occurring together, then the total probability should be equal to 1. But this does not work in this case;

In this case, adding all the probabilities together, we have;

1/12 + 1/12 + 1/12 + 1/12 + 1/12 + 1/2

= 5(1/12) + 1/2 = 5/12 + 1/2 = 11/12

11/12 is not equal to 1 and thus the probability distribution cannot be correct

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3 years ago