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notka56 [123]
3 years ago
5

The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

y=\frac{1}{20}x^2

Step-by-step explanation:

In this problem

we have

F(0,5)  and directrix at y=-5

so

Is a vertical parabola open upward

we know that

The equation of a vertical parabola in standard form is

(x-h)^2=4p(y-k)

where

p is the focal distance

(h,k) is the vertex

we have

The vertex is the origin (0,0)

and

p=5

substitute

(x-0)^2=4(5)(y-0)

x^2=20y

y=\frac{1}{20}x^2

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Step-by-step explanation:

1) i will asume x2 and z2 are squares here.

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7 0
3 years ago
Pls help i would love to have an explanation of how you got the answer<br>i will mark brainliest
Neporo4naja [7]
Answer :
i what explanation can u post the picture
5 0
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Please help me now please
nadezda [96]
A2+B2=C2

12(2)+B(2)=27.1(2)

24+B=54.2
-24 -24
——————
B=30.2

Answer is 30.2
I hope this helps
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answer
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