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notka56 [123]
3 years ago
5

The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

y=\frac{1}{20}x^2

Step-by-step explanation:

In this problem

we have

F(0,5)  and directrix at y=-5

so

Is a vertical parabola open upward

we know that

The equation of a vertical parabola in standard form is

(x-h)^2=4p(y-k)

where

p is the focal distance

(h,k) is the vertex

we have

The vertex is the origin (0,0)

and

p=5

substitute

(x-0)^2=4(5)(y-0)

x^2=20y

y=\frac{1}{20}x^2

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