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3 years ago

The equation of the parabola whose focus is at (0, 5) and directrix at y = -5 is:

Mathematics

1 answer:

Jlenok [28]3 years ago

3 0

Answer:

$y=\frac{1}{20}x^2$

Step-by-step explanation:

In this problem

we have

F(0,5) and directrix at y=-5

Is a vertical parabola open upward

we know that

The equation of a vertical parabola in standard form is

$(x-h)^2=4p(y-k)$

where

p is the focal distance

(h,k) is the vertex

we have

The vertex is the origin (0,0)

and

p=5

substitute

$(x-0)^2=4(5)(y-0)$

$x^2=20y$

$y=\frac{1}{20}x^2$

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4 years ago

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Step-by-step explanation:

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3 years ago

Can you help me find the volume base area latera area and total area please to this problem

krek1111 [17]

Answer:

BA = 25π,

LA = 25√2π,

TA = 25π + 25√2π,

V = 41 and 2 / 3π

Step-by-step explanation:

We need to determine the height here, as it is not given, and is quite important to us. The height is a perpendicular line segment to the radius, hence forming a 45 - 45 - 90 degree triangle as you can see. Therefore, by " Converse to Base Angles Theorem " the height should be equal in length to the radius,

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The lateral area is simply the surface area excluding the base area, the surface area having a formula of " πr^2 + πrl. " Thus, the lateral area can be calculated through the formula " πrl, " but as we are not given the slant height ( l ) we have to use another formula, $l= \sqrt{r^2+h^2}$ -