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Alexeev081 [22]
4 years ago
15

Imagine two line segments where each represents a slant height of the cone. The segments are on opposite sides of the cone and m

eet at the apex. Find the measurement of the angle formed between the line segments.

Mathematics
2 answers:
sladkih [1.3K]4 years ago
8 0

Imagine that we cut the cone in half with a vertical plane. In this plane we'd see points a, b and c. We need to find the measure of angle bca, and then double that angle, to obtain the answer to this problem.

Note that tan (angle bca) = opp / adj = 2 / 6, or 1/3, or 0.333...

Working backwards to find angle bca, we use the inverse tangent function:

arctan 0.3333.. = approx. 0.322 radians, or 18.435 degrees.

Doubling that gives us the measurement of the angle formed between the line segments: 2(18.435 deg) = 36.9 degrees, approximately.

noname [10]4 years ago
5 0

Imagine that we cut the cone in half with a vertical plane. In this plane we'd see points a, b and c. We need to find the measure of angle bca, and then double that angle, to obtain the answer to this problem.

Note that tan (angle bca) = opp / adj = 2 / 6, or 1/3, or 0.333...

Working backwards to find angle bca, we use the inverse tangent function:

arctan 0.3333.. = approx. 0.322 radians, or 18.435 degrees.

Doubling that gives us the measurement of the angle formed between the line segments: 2(18.435 deg) = 36.9 degrees, approximately.

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The slope intercept form: y = - 5x + 7

Step-by-step explanation:

The equation of line f is y − 9 = -5(x + 7)

You need to find the slope of line f

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In point slope form: y - y1 = m(x - x1) where m = slope

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Parallel lines, slope is the same so slope of line g is also equal - 5

Line g passes through (3, - 8) so equation in point slope form:

y + 8 = -5(x - 3)

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3 years ago
What is the slope of the line that contains the point (13,-2) and (3,-2)
ra1l [238]

The slope of the line that contains the point (13,-2) and (3,-2) is 0

<em><u>Solution:</u></em>

Given that we have to find the slope of the line

The line contains the point (13,-2) and (3,-2)

<em><u>The slope of line is given as:</u></em>

m = \frac{y_2-y_1}{x_2-x_1}

Where, "m" is the slope of line

Here given points are (13,-2) and (3,-2)

(x_1, y_1) = (13, -2)\\\\(x_2, y_2) = (3, -2)

<em><u>Substituting the values in formula, we get,</u></em>

m = \frac{-2-(-2)}{3-13}\\\\m = \frac{-2+2}{3-13}\\\\m = 0

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