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worty [1.4K]
3 years ago
8

Identify the vertex and the y-intercept of the graph of the function y=-2(x+3)^2 +2.

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

we can simplify it to this:

y =  - 2 {x}^{2} - 12x - 16

so we know it , the intercept in a standard equation of a parabola is C:

a {x}^{2}  + bx + c

so the intercept is (-16) and for the vertex use:

x=-b/2a

x =  \frac{12}{ - 4} =  - 3

so now put it in the equation and get the y of vertex:

y=-18+36-16=2 ==>vertex(-3,2)

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