Question

Identify the vertex and the y-intercept of the graph of the function y=-2(x+3)^2 +2.

Answer 1

we can simplify it to this:

$y = - 2 {x}^{2} - 12x - 16$

so we know it , the intercept in a standard equation of a parabola is C:

$a {x}^{2} + bx + c$

so the intercept is (-16) and for the vertex use:

x=-b/2a

$x = \frac{12}{ - 4} = - 3$

so now put it in the equation and get the y of vertex:

y=-18+36-16=2 ==>vertex(-3,2)