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Marat540 [252]
3 years ago
8

Find the interquartile range for a data set having the five-number summary: 4.9, 12.4, 20.5, 28.8, 34.3

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

16.4

Step-by-step explanation:

The interquartile range is the difference between the upper and lower quartiles.

Given the five figure summary, then

upper quartile = 28.8

lower quartile = 12.4

interquartile range = 28.8 - 12.4 = 16.4

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Which of the following shows a group of possible angles a triangle could have?
Delvig [45]

Answer:

C. 60 degrees, 60 degrees, 60 degrees

Step-by-step explanation:

The measures of interior angles of a triangle sum to 180°.

8 0
3 years ago
A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The poi
nalin [4]
Circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
points (-3,2) and (1,5)
D=\sqrt{(1-(-3))^{2}+(5-2)^{2}}
D=\sqrt{(4)^{2}+(3)^{2}}
D=\sqrt{16+9}
D=\sqrt{25}
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle



radius=5 units
the points (-7,5) and (-7,1) lie on this circle

3 0
3 years ago
Ms.Lamberson got a new puppy abd weighed it in September and October in September the Puppy Weighed9 and one Fourth pounds In Oc
ddd [48]

Answer: The puppy was 2.25\ lb havier in October that it was in September.

Step-by-step explanation:

You need to make the conversion from mixed numbers to decimal numbers. To do it, divide the numerator of the fraction by the denominator add the result to whole part number:

9\frac{1}{4}=9+0.25=9.25\\\\11\frac{1}{2}=11+0.5=11.5

The weight of the puppy in September was:

w_1=9.25\ lb

And its weight in October was:

w_2=11.5\ lb

Subtract its weight in September from its weight in October in order to find how much heavier the puppy was in October than it was in September:

w_2-w_1=11.5\ lb-9.25\ lb=2.25\ lb

8 0
3 years ago
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