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Marat540 [252]
4 years ago
8

Find the interquartile range for a data set having the five-number summary: 4.9, 12.4, 20.5, 28.8, 34.3

Mathematics
1 answer:
Kamila [148]4 years ago
5 0

Answer:

16.4

Step-by-step explanation:

The interquartile range is the difference between the upper and lower quartiles.

Given the five figure summary, then

upper quartile = 28.8

lower quartile = 12.4

interquartile range = 28.8 - 12.4 = 16.4

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Answer:

Step-by-step explanation:

Well, the 1 is in the tens place. Soooo then you add the three and then add a 0, the answer will be 30% (Sorry if that didn't make sense I tried!)

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please help 1.Bryce started with $450 in a bank account that does not earn interest. In the middle of every month, he withdraws
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Since during middle of each month, Bryce withdraws half of his amount. So at the end of each month, his balance is 1/2 times as compared to balance of his previous month.

The following recursive function represents the Brye's balance at end of each month:

a_{n}= \frac{1}{2}* a_{n-1}

where a_{n-1} is the account balance of previous month. And a_{n} is the account balance of current month. 


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3 years ago
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Mrac [35]
1/3 divided by 5 and 1/3 x 1/5 are both correct
7 0
3 years ago
Given f(x)=4X+9, find the equation for f^-1(x)
Ilia_Sergeevich [38]

Answer:

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6 0
4 years ago
A poll finds that 54% of the 600 people polled favor the incumbent. Shortly after the poll is taken, it is disclosed that the in
egoroff_w [7]

Answer:

There is not enough evidence to support the claim that the proportion that polled in favor of the incumbent has decreased significantly (P-value=0.06).

Test statistic z=1.56.

 

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion that polled in favor of the incumbent has decreased significantly.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (old poll), of size n1=600 has a proportion of p1=0.54.

The sample 2 (new poll), of size n2=1030 has a proportion of p2=0.5.

 

The difference between proportions is (p1-p2)=0.04.

p_d=p_1-p_2=0.54-0.5=0.04

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{324+515}{600+1030}=\dfrac{839}{1630}=0.5147

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.5147*0.4853}{600}+\dfrac{0.5147*0.4853}{1030}}\\\\\\s_{p1-p2}=\sqrt{0.0004+0.0002}=\sqrt{0.0007}=0.0257

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.04-0}{0.0257}=\dfrac{0.04}{0.0257}=1.56

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

\text{P-value}=P(z>1.56)=0.06

As the P-value (0.06) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion that polled in favor of the incumbent has decreased significantly.

5 0
4 years ago
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