Using the it's concept, the correct calculation for the probability of choosing a red grape and then without putting the red grape back into the bowl, choosing a green grape is:
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, we have that there is a total of 6 + 10 + 8 = 24 grapes. For the first grape, 10 are red, hence the probability that the first grape is red is:
For the second grape, considering that the first was red and was removed, there will be 23 grapes, out of which 6 will be green, hence the probability that the second grape is green is:
Hence the correct expression is found as follows:
More can be learned about probabilities at brainly.com/question/14398287
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