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Sliva [168]
2 years ago
7

A ____________ variable is available throughout a program.

Computers and Technology
1 answer:
kvv77 [185]2 years ago
3 0

Answer:

global

Explanation:

Its the global variable, and its scope is the whole program. And hence, a global variable is available throughout the program. And you need to know that a local variable has its scope in the block where it has been declared. Its scope is that block or the function or the loop only. And if you want it to have a global scope, then you will have to declare it as a global variable.

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In Scratch, you have to choose backdrops from a limited number in the Scratch image library.
forsale [732]
I would say it would be True
5 0
3 years ago
Write the definition of the function inputArray that prompts the user to input 20 numbers and stores the numbers into alpha. Wri
Alina [70]

Answer:

In Java:

public static  int[] inputArray(){

   Scanner input = new Scanner(System.in);

   int[] alpha = new int[20];

   for(int i = 0;i<20;i++){

       alpha[i] = input.nextInt();

   }

   return alpha;}

public static  int[] doubleArray(int [] alpha){

   int[] beta = new int[20];

   for(int i = 0;i<20;i++){

       beta[i] = 2 * alpha[i];

   }

   return beta;

}

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

   int [] AlphaBeta = new  int[10];

   for(int i = 0;i<5;i++){

       AlphaBeta[i] = alpha[i];

   }

   int count = 5;

   for(int i = 15;i<20;i++){

       AlphaBeta[count] = beta[i];

       count++;

   }

   return AlphaBeta;

}

public static void printArray(int [] alpha){

   for(int i = 0;i<20;i++){

       System.out.print(alpha[i]+" ");

       if((i+1)%15 == 0){

           System.out.println(" ");

       }

   }

}

Explanation:

The inputArray is defined here

public static  int[] inputArray(){

   Scanner input = new Scanner(System.in);

This declares alpha array of 20 elements

   int[] alpha = new int[20];

The following iteration gets input from the user into the array

<em>    for(int i = 0;i<20;i++){</em>

<em>        alpha[i] = input.nextInt();</em>

<em>    }</em>

This returns the alpha array

   return alpha;}

The doubleArray is defined here. It takes the alpha array as its input parameter

public static  int[] doubleArray(int [] alpha){

This declares beta of 20 integers

   int[] beta = new int[20];

This populates beta by 2 * alpha[i]

<em>    for(int i = 0;i<20;i++){</em>

<em>        beta[i] = 2 * alpha[i];</em>

<em>    }</em>

This returns the alpha array

   return beta;}

The copyAlphaBeta array is defines here

public static int[] copyAlphaBeta(int [] alpha, int [] beta){

This declares AlphaBeta as 10 elements

   int [] AlphaBeta = new  int[10];

This populates the first 5 elements of AlphaBeta with the first 5 of alpha

<em>    for(int i = 0;i<5;i++){</em>

<em>        AlphaBeta[i] = alpha[i];</em>

<em>    }</em>

   int count = 5;

This populates the last 5 elements of AlphaBeta with the last 5 of beta

<em>    for(int i = 15;i<20;i++){</em>

<em>        AlphaBeta[count] = beta[i];</em>

<em>        count++;</em>

<em>    }</em>

This returns the AlphaBeta array

   return AlphaBeta;

}

The printArray is defined here. It takes the alpha array as its input parameter

public static void printArray(int [] alpha){

This iterates through alpha array

   for(int i = 0;i<20;i++){

This prints each element of the array

       System.out.print(alpha[i]+" ");

A new line is started after the 15th element

<em>        if((i+1)%15 == 0){</em>

<em>            System.out.println(" ");</em>

<em>        }</em>

   }

}

See attachment for complete program which includes the main

Download txt
4 0
2 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
Assume values 10, 20, 30, and 40 are entered in the cell range A1:A4. Cell A10 contains the formula: =A1+A2+A3+A4 and displays v
r-ruslan [8.4K]

Answer:

The formula and value to this question is "=A1+A3+A4+A5 with value 100"

Explanation:

The explanation of the given question as follows:

  • In question, it is defined that four cells that are "A1, A2, A3, and A4"  contains value that are "10, 20, 30, and 40".
  • To add these values we use addition formula that is "=A1+A2+A3+A4". it will give value 100.
  • If the user inserts a new row that is "A2" and assigns a value in the cell that is "50" so, we use the above formula that adds values with these values we also use the value "100".
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2 years ago
Multibeam sonar technology uses _____.
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More than one sound source and listening device<span>
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8 0
3 years ago
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