So this question is already perfectly set up. Since the 6 and -6 cancel you’ll be left with 5x + 3x which is 8x and -32 + 48 which is 16. 8x=16. Isolate x to get that x=2. Plug 2 back into one of the equations. 5(2) -6y = -32. Solve for y now. -10-32 equals -42. Divide -42 by -6 to get 7. So the final coordinate where the two equations will intersect is (2,7)
The answer is b)04 I did this on my test and got it correct
Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
Answer:
1) 
2) 
3) see below
4) A: 0 = 1
Step-by-step explanation:
<u>Question 1</u>
<u>Question 2</u>
<u>Question 3</u>
subtract the second equation from the first
divide both sides by -4
substitute found value for y into first equation
solve for x
<u>Question 4</u>
Solution = A
Its lowest terms are 1/16
