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julia-pushkina [17]
2 years ago
15

Consider two events, P and Q. The probability of event P occurring is 16. The probability of event Q occurring is 23. Which stat

ement is true?
Mathematics
1 answer:
garri49 [273]2 years ago
7 0

The event "P and Q" is a compound event in the probability, and the true statement about the probability is P(P and Q) = 1/9

<h3>How to determine the true statement?</h3>

The probabilities are given as:

P(P) = 1/6

P(Q) = 2/3

The probability of the event P and Q is calculated using:

P(P and Q) = P(P) * P(Q)

This gives

P(P and Q) = 1/6 * 2/3

Evaluate the product

P(P and Q) = 1/9

Hence, the true statement about the probability is P(P and Q) = 1/9

Read more about probability at:

brainly.com/question/251701

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Create write an expression that simplifies to 2a + 14 using the distributive property
geniusboy [140]

Answer:

2 ( a + 7)

Step-by-step explanation:

2a + 14

both 2a and 14 are divisible by 2

2a/a = a

14/2 = 7

2( a + 7) = 2a + 14

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

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4 0
3 years ago
Offering 20 points to whoever answers all of themmmmmmm!
s2008m [1.1K]

Answer:

The first is 30

Step-by-step explanation:

The third is 115

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Two times the sum of a number and 22 is atleast -28<br><br> please hurry
Marta_Voda [28]

Answer:

-6

Step-by-step explanation:

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6 0
3 years ago
What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti
Marat540 [252]

Answer:

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

Step-by-step explanation:

Given

x^2 - 5x - 7 = 0

Required

Solve for x using:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

First, we need to identify a, b and c

The general form of a quadratic equation is:

ax^2 + bx + c = 0

So, by comparison with x^2 - 5x - 7 = 0

a = 1     b = -5      c = -7

Substitute these values of a, b and c in

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}

x = \frac{5 \± \sqrt{25 +28}}{2}

x = \frac{5 \± \sqrt{53}}{2}

Split the expression to two

x = \frac{5 + \sqrt{53}}{2}  or  x = \frac{5 - \sqrt{53}}{2}

To solve further in decimal form, we have

x = \frac{5 + 7.28}{2}  or  x = \frac{5 - 7.28}{2}

x = \frac{12.28}{2}  or  x = \frac{-2.28}{2}

x = 6.14 or x = -1.14

4 0
3 years ago
I need the answers to these questions please people on here?
Effectus [21]
2. 225
4. 25/36
6. 0.001
8. 8-20=-12
10. 34-16=18
12. 15/5=3^3=27
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16. 8
18. 11.5+4=15.5
20. 3(225)+10=675+10=685
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3 years ago
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