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irina1246 [14]
3 years ago
14

Three times a number, less 4 is 2

Mathematics
1 answer:
tekilochka [14]3 years ago
3 0

Answer:

2

Step-by-step explanation:

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How do you get statistics from percentages
Nikitich [7]

Answer:

Divide the target demographic by the entire population, and then multiply the result by 100 to convert it to a percentage.  

Step-by-step explanation:

Gather Your Statistics.

Divide by Entire Population.

Convert to Percentage

6 0
3 years ago
I need help please!!
Sergio039 [100]

Answer:

16 cm2

Step-by-step explanation:

By equa tion of area of triangle: S = 1/2 * height * base

Triangle B: 32  = 1/2 * 8 * x --> x = 8 (cm)

The base of triangle A is half of the base of triangle B so it is 4 cm.

The area of triangle A = 1/2 * 8 * 4 = 16 (cm2)

5 0
2 years ago
A figure is made up of a triangle and a rectangle. The triangle has a height of 8.5 inches and a base of 10 inches. The rectangl
Brilliant_brown [7]

\sf  are a \  of \   triangle : \frac{1}{2}*base *height

\sf  are a \  of \   rectangle : Length * Width

total area :

\sf  are a \  of \   rectangle  + area \ of \  triangle

\rightarrow  \sf 9 * 10 + \frac{1}{2} *8.5*10

\rightarrow  \sf 132.5 \ in^2

5 0
2 years ago
What is 9/7 times -9/5?
pochemuha

Answer:

- 2 11/35

Step-by-step explanation:

Step 1:

9/7 × - 9/5     Equation

Step 2:

- 81/35      Multiply

Answer:

- 2 11/35       Convert

Hope This Helps :)

8 0
2 years ago
A spherical balloon is inflated so that its volume is increasing at the rate of 3 ft3/min. How fast is the diameter of the ballo
beks73 [17]

When an spherical balloon volume is increasing at the rate of 3ft^3/min then the diameter of the balloon is increasing \frac{3}{2\pi }ft /min

How can we find the rate of change of balloon's diameter ?

The volume of a spherical balloon is v=\frac{4}{3} \pi r^3

In form of diameter we can write as

v=\frac{4}{3} \pi (\frac{D}{2} )^3\\=\frac{1}{6} \pi D^3

Now we will differentiate both sides wrt to t we get

\frac{dv}{dt} =\frac{1}{6} \pi 3D^2 \frac{dD}{dt} \\\frac{dD}{dt} =\frac{2}{\pi D^2} \frac{dv}{dt} \\\\when r=1\\D=2ft

Given in the question \frac{dv}{dt} =3ft^3/min

thus when we substitute the values we get

\frac{dD}{dt} =\frac{2}{\pi *2^2} (3)\\\frac{dD}{dt}=\frac{3}{2\pi }  ft/min

Learn more about the differentiation here:

brainly.com/question/28046488

#SPJ4

3 0
2 years ago
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