Answer: The answer is ![\textup{The other root is }\dfrac{8}{3}~\textup{and}q=40.Step-by-step explanation: The given quadratic equation is[tex]3x^2+7x-q=0\\\\\Rightarrow x^2-\dfrac{7}{3}x-\dfrac{q}{3}=0.](https://tex.z-dn.net/?f=%5Ctextup%7BThe%20other%20root%20is%20%7D%5Cdfrac%7B8%7D%7B3%7D~%5Ctextup%7Band%7Dq%3D40.%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%20%20%3C%2Fstrong%3EThe%20given%20quadratic%20equation%20is%3C%2Fp%3E%3Cp%3E%5Btex%5D3x%5E2%2B7x-q%3D0%5C%5C%5C%5C%5CRightarrow%20x%5E2-%5Cdfrac%7B7%7D%7B3%7Dx-%5Cdfrac%7Bq%7D%7B3%7D%3D0.)
Also given that -5 is one of the roots, we are to find the other root and the value of 'q'.
Let the other root of the equation be 'p'. So, we have

and

Thus, the other root is
and the value of 'q' is 40.
Answer:
8/21
I don't think that it can be simplified further....
Answer:
you too
Step-by-step explanation:
Let

Differentiating twice gives


When x = 0, we observe that y(0) = a₀ and y'(0) = a₁ can act as initial conditions.
Substitute these into the given differential equation:


Then the coefficients in the power series solution are governed by the recurrence relation,

Since the n-th coefficient depends on the (n - 2)-th coefficient, we split n into two cases.
• If n is even, then n = 2k for some integer k ≥ 0. Then




It should be easy enough to see that

• If n is odd, then n = 2k + 1 for some k ≥ 0. Then




so that

So, the overall series solution is

