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s2008m [1.1K]
4 years ago
15

Somebody plz me on this real quick

Mathematics
1 answer:
Kay [80]4 years ago
4 0
I think it would be the second one
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Which set of ordered pairs does not represent a function?
frosja888 [35]

Answer:

(-7,8), (2,1),(-8, -9), (-8,6)

Step-by-step explanation:

the x values repeat

The x values are not supposed to repeat to create a function

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There’s a 75% chance that everyone in the group is a girl
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Choose the simplified product.
nikitadnepr [17]

Answer:

I need answer choices to help you hone in on one specific answer but Simplify the radical by breaking the radicand up into a product of known factors

Step-by-step explanation:

4 0
4 years ago
Let F(x, y, z) = (5ex sin(y))i + (5ex cos(y))j + 7z2k. Evaluate the integral C F · ds, where c(t) = 8 t , t3, exp( t ) , 0 ≤ t ≤
maria [59]

I'm going to assume this reads

\vec F(x,y,z)=5e^x\sin y\,\vec\imath+5e^x\cos y\,\vec\jmath+7z^2\,\vec k

and the path C is parameterized by

\vec c(t)=8t\,\vec\imath+t^3\,\vec\jmath+e^t\,\vec k

with 0\le t\le1. Under this parameterization,

\vec F(x,y,z)=\vec F(x(t),y(t),z(t))=5e^{8t}\sin(t^3)\,\vec\imath+5e^{8t}\cos(t^3)\,\vec\jmath+7e^{2t}\,\vec k

and

\mathrm d\vec c=\dfrac{\mathrm d\vec c}{\mathrm dt}\,\mathrm dt=(8\,\vec\imath+3t^2\,\vec\jmath+e^t\,\vec k)\,\mathrm dt

Then in the integral,

\displaystyle\int_C\vec F\cdot\mathrm d\vec s=\int_0^1\vec F(x(t),y(t),z(t))\cdot\frac{\mathrm d\vec c}{\mathrm dt}\,\mathrm dt

=\displaystyle\int_0^1(7e^{3t}+15e^{8t}t^2\cos(t^3)+40e^{8t}\sin(t^3))\,\mathrm dt\approx\boxed{12586.5}

(It's unlikely that an exact answer can be found in terms of elementary functions)

4 0
3 years ago
Compute <img src="https://tex.z-dn.net/?f=i%2Bi%5E2%2Bi%5E3%2B%5Ccdots%2Bi%5E%7B258%7D%2Bi%5E%7B259%7D" id="TexFormula1" title="
xz_007 [3.2K]

Answer:

-1

Step-by-step explanation:

Note that i+i^2+i^3+i^4 = i-1-i+1 = 0, and this means that every 4 terms, the terms cancel to 0. Therefore, by taking modulo 4, we only need to find i^{257}+i^{258}+i^{259} = i-1-i = -1 since $i$ has a cycle of 4.

3 0
3 years ago
Read 2 more answers
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