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2 years ago

Write an expression for the area of the triangle below.

Mathematics

1 answer:

vfiekz [6]2 years ago

7 0

It should be A= 1/2bh but im not sure why you wrote those extra things. Are we supposed to use them?

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8090 [49]

0.5477225575 ... u have to change this in scientific notation

3 0

2 years ago

Please factor 5x^2-23x+12

STALIN [3.7K]

5x^2-23x+12

= 5x^2 - 20x - 3x + 12

= 5x(x - 4) - 3(x - 4)

= (5x - 3)(x - 4)

Hope that helps

3 0

2 years ago

End behavior of f(x)=-4(1/2)^x+4

kkurt [141]

Answer:

x=0

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is the graph of the function f(x) = the quantity of x plus 2, all over x minus 3

Andrej [43]

Answer:

Step-by-step explanation:

The given function is $f(x)=\frac{x+2}{x-3}$ and we need to graph it.

In order to graph this function, we'll find below things:

Horizontal asymptote:

Since the degree of both numerator and denominator is same. Hence, the horizontal asymptote is the ratio of leading coefficient of numerator to the leading coefficient of denominator.

Horizontal asymptote is y = 1/1 = 1

Vertical asymptote:

Vertical asymptote occurs where the denominator is zero.

$x-3=0\\x=3$

x-intercepts:

For x-intercept, y = 0

$\frac{x+2}{x-3}=0\\\\x+2=0\\x=-2$

y-intercepts:

For y-intercept, x= 0

$y=\frac{0+2}{0-3}=0\\\\y=-\frac{2}{3}$

Using these, we can draw the graph of the rational expression.

5 0

2 years ago

Read 2 more answers

The equation 7^2=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

jeyben [28]

Answer:

The period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

Step-by-step explanation:

The equation $T ^ 2 = a ^ 3$ shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?

For the planet Y:

$T_y ^ 2 = a_y ^ 3$

For planet X:

$T_x ^ 2 = a_x ^ 3$

To know the factor of aumeto we compared $T_x$ with $T_y$

We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:

$a_y ^ 3 = (a_xk) ^ 3$

$\frac{T_y ^ 2}{T_x ^ 2}=\frac{a_y ^ 3}{a_x^ 3}\\\\\frac{T_y ^ 2}{T_x ^ 2}=\frac{(a_xk)^3}{a_x ^ 3}\\\\\frac{T_y^ 2}{T_x^ 2}=\frac{k ^ {3}a_{x}^ 3}{a_{x}^ 3}\\\\\frac{T_{y}^ 2}{T_{x}^ 2}=k ^ 3\\\\T_{y}^ 2 = T_{x}^{2}k^{3}\\\\T_{y} =k^{\frac{3}{2}}T_x$

Then, the period of Y increases by a factor of $k^ {3/2}$ with respect to the period of X

4 0

3 years ago