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azamat
2 years ago
14

WILL MARK BRAINLIEST NEED ANSWER ASAP!!

Mathematics
2 answers:
Ganezh [65]2 years ago
7 0

Answer:

Step-by-step explanation:

the answer is a irrational

MA_775_DIABLO [31]2 years ago
5 0
The Answer you want is c
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A taxicab company charges $3.10 plus $0.60 per mile. Carmen paid a fare of $10.90. Enter and solve an equation to find the numbe
9966 [12]

Answer:

13 miles

Step-by-step explanation:

The taxicab charges a fixed amount of $3.10 plus $0.60 per mile.

This can be modeled by the equation.

f= 0.60m + 3.10

where f is the total fare and m is the number of miles traveled.

If Carmen paid a fare of $10.90, then we substitute for f and solve for m.

0.6m + 3.10 = 10.90

0.6m = 10.90 - 3.10

0.6m = 7.8

m =  \frac{7.8}{0.6}

m = 13

Therefore Carmen traveled 13 miles.

8 0
3 years ago
Find the value of D that makes the fraction equivalent
IgorLugansk [536]

40 I hope I helped you

6 0
3 years ago
Read 2 more answers
Kero has a plastic container in the shape of a cube. The length of a side is 20 cm. She wants to fill it with 3 liters of water.
ankoles [38]
The answer is yes cause 12000>3000
6 0
3 years ago
One side of triangle is 7 more than 2 times the shortest side. the third side is 15 centimeters more than the shortest side. the
nikdorinn [45]
X = longest side , y = middle side , z = shortest side 

P = x + y + z
P = 82
x = 2z + 7
y = z + 15

82 = (2z + 7) + (z + 15) + z...combine like terms
82 = 4z + 22
82 - 22 = 4z
60 = 4z
60/4 = z
15 = z

so the shortest side (z) is 15 cm
the second side (y) is : z + 15......15 + 15 = 30 cm
and the longest side (x) is : 2z + 7.....2(15) + 7 = 37 cm

7 0
3 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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