I NEED SOMEONE FROM RSM 7TH GRADE TO COME AND HELP ME ASAP PLZ!!!!!!!!!!!!

Mathematics

1 answer:

Aneli [31]2 years ago

4 0

Answer:

I don't see any problem or I would help u out

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Nicolas has $650 to deposit into two different savings accounts. • Nicolas will deposit $400 into Account I, which earns 3.5% an

Alinara [238K]

C) $694.25

Why?
Because you want to times the interest by 2 (1 is for one year but u want to find the amount after two years) then you multiply the amount given to each bank separately so:

400*0.07 (7% which is 7/100) = 28
250*0.065 (6.5% which is 65/1000) = 16.25

Then u add the interests together:
28+16.25 = 44.25

Finally you add that to the amount you started with:
$650+$44.25= $694.25

5 0

3 years ago

What is the volume of a hemisphere with a radius of 1.6 and height of 6.2?

qaws [65]

You can find the area of a hemisphere by using the following equation

V = (2/3) (pi)*r^3

so V = (2/3) (pi)*1.6^3

Which comes out as 8.5786423394 or 8.6

6 0

3 years ago

What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$