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MariettaO [177]
3 years ago
5

The maritime museum has 100 ship models. Visitors can see 90% of the ships in a special exhibit. How many ships can visitors see

in the special exhibit?
A. 9

B. 10

C.90

D.99
Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
90% of 100 = 0.9 x 100 = 90

------------------------------------------------
Answer: The visitor can see 90 ships.
------------------------------------------------
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SOMEONE ANWSER QUICK !
xenn [34]

Answer:

I think that the answer would be C because you have to multiply the term at the top. This would mean you would not do C. Sorry if this is wrong. At least you have your eliminating process now. lol so doing C is out of the box, which makes C your answer.

Step-by-step explanation:

6 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
rick deposited $6200 in a savings account with simple interest. three years later, the account held $7130 what was the interest
Law Incorporation [45]

1) Gathering the data

P=$6200

F=7310

t= 3 yrs

2) Since it is a simple interest, it is a linear application. So we can find it using this formula:

undefined

8 0
2 years ago
If two lines are perpendicular to each other, do they lie in the same plane?
Arada [10]
Yes they do, Hope this helps :p
8 0
3 years ago
Sumas y restas w+y=9 3w-y=11
Westkost [7]

Answer:

w = 5

y = 4

Step-by-step explanation:

w+y=9

3w-y=11

4w = 20

w = 5

y = 4

3 0
3 years ago
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