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2 years ago

Make g the subject of the formula r = 4g +7

Mathematics

2 answers:

mafiozo [28]2 years ago

8 0

Answer:

4 better explanation inbox

Step-by-step explanation:

NISA [10]2 years ago

5 0

Answer:

Answer: g = r - 7 * 4.

Step-by-step explanation:

that's the answer

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Find the product (8/6n-4)(9n^2-4)

Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

$(\frac{8}{6n-4})(9n^{2}-4)$

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

$=\frac{8(9n^2-4)}{6n-4}$

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

$a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}$

We can take 2 as common factor from denominator

$=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)$

Hence the product is 4(3n+2) or 12n+8 ..

6 0

2 years ago

12(3+m) A.36m B.36+m C.36+12m D.3m+12m PLEASSSSEEE HELP ASAP 15

kherson [118]

Answer:

C. 36+12m

Step-by-step explanation:

When you distribute a number outside the parenthesis, you multiply it to all numbers nor letters in the parenthesis. Hopes this helps

8 0

2 years ago

Solve for x:a(a²+b²)x²+b²x-a

m_a_m_a [10]

Answer:

x = a/(a² + b²) or x = -1/a

Step-by-step explanation:

a(a²+ b²)x² + b²x - a =0

Use the quadratic equation formula:

$x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} =\dfrac{-b\pm\sqrt{D}}{2a}$

1. Evaluate the discriminant D

D = b² - 4ac = b⁴ - 4a(a² + b²)(-a) = b⁴ + 4a⁴ + 4a²b² = (b² + 2a²)²

2. Solve for x

$\begin{array}{rcl}x & = & \dfrac{-b\pm\sqrt{D}}{2a}\\\\ & = & \dfrac{-b^{2}\pm\sqrt{(b^{2}+2a^{2})^{2}}}{2a(a^{2} + b^{2})}\\\\ & = & \dfrac{-b^{2}\pm(b^{2}+ 2a^{2})}{2a(a^{2} + b^{2})}\\\\x = \dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}\\\\x =\dfrac{-b^{2}+(b^{2} + 2a^{2})}{2a(a^{2} + b^{2})}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\\end{array}$

$\begin{array}{rcl}x = \large \boxed{\mathbf{\dfrac{a}{a^{2} + b^{2}}}}&\qquad& x =\dfrac{-b^{2}-(b^{2} +2a^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2b^{2}- 2a^{2}}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\dfrac{-2(a^{2}+ b^{2})}{2a(a^{2} + b^{2})}\\\\&\qquad& x =\large \boxed{\mathbf{-\dfrac{1}{a}}}\\\\\end{array}$

5 0

3 years ago

Does anyone know the answer to this? If you do please answer!

enot [183]

Answer:

The Y axes

Step-by-step explanation:

4 0

2 years ago

Zebras migrate in a circle with a round trip of about 300 miles. They travel at 64 km/h. How many hours does it take zebra to do

Tresset [83]

Answer:

7.5 hours (7 hours and 30 minutes)

Step-by-step explanation:

ok Let's start with 64km/h.

1.6 km=1 mile,

64÷1.6=40miles

so 64km/h changes into 40miles/hour.

Zebras's round trip =300miles,

300/40=7.5

so answer is 7.5 hours.

8 0

3 years ago

Make g the subject of the formula r = 4g +7​

Make g the subject of the formula r = 4g +7