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3 years ago

If n = 37 cm and l = 12 cm, what is the length of m?

Mathematics

1 answer:

Svetllana [295]3 years ago

7 0

Isn't there suppose to be an equation or something that you have to solve?

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Bessie has an annual salary of $51,360. Each month she has a car payment of $210 and a student loan of$50. If she applies for a

Svetach [21]

Every month she makes 4280 usd. $51,360/12 months...she pays her debt ($260) a month.....she will be approved. 1:16 Ratio

6 0

3 years ago

Please help me please

ella [17]

Answer:

-4??

Step-by-step explanation:

4 0

2 years ago

Find the coordinates of the midpoint of a segment having the given endpoints.

inysia [295]

Answer:

A. (1.55, 2)

Step-by-step explanation:

The formula to apply when finding the midpoint of a segment where the coordinates of the end points are given is;

$midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$

where (x₁,y₁) and (x₂,y₂) are the coordinates of the end points

Given;

x₁= -0.4 ,y₁=2.5, x₂=3.5, y₂=1.5 then applying the formula for midpoint

$=(\frac{-0.4+3.5}{2} ,\frac{2.5+1.5}{2} )\\\\\\=(\frac{3.1}{2} ,\frac{4.0}{2} )\\\\\\=(1.55,2.0)$

3 0

3 years ago

Please help me answer 16 please

amm1812

Answer:

SSS

Step-by-step explanation:

I can identify that these triangles are congruent by using the SSS (Side, Side, Side) postulate theorem. I know this because first, second, and home triangle share the same side as the third, second, and home triangle, meaning they are congruent, so are the other sides of the angle since the question states they are congruent.

5 0

3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0

3 years ago