Question

What is an equation for the line that passes through (-2,-3) with a slope of -1/2?

Answer 1

Answer:

C

Step-by-step explanation:

To write the equation of a line use the point slope form of a line substituting m = -1/2 and the point (-2,-3).

$y -y_1 = m(x-x_1)\\y --3=-\frac{1}{2}(x--2)\\y+3 = -\frac{1}{2}(x+2)$

Convert to standard form by applying the distributive property and rearranging the terms.

$y + 3 = -\frac{1}{2}(x+2)\\y+3 = -\frac{1}{2}x -1\\2y + 6 = -x -2\\x+2y + 6 = -2\\x + 2y = -8$

The equation x +2y = -8 is the same equation as 4y + 2x = -16 just doubled----> 2x + 4y = -16