Answer:
6.5 x 10^6 To answer this question, you need to divide the mass of the sun by the mass of mercury. So 2.13525 x 10^30 / 3.285 x 10^23 = ? To do the division, divide the mantissas in the normal fashion 2.13525 / 3.285 = 0.65 And subtract the exponents. 30 - 23 = 7 So you get 0.65 x 10^7 Unless the mantissa is zero, the mantissa must be greater than or equal to 0 and less than 10. So multiply the mantissa by 10 and then subtract 1 from the exponent, giving 6.5 x 10^6 So the sun is 6.5 x 10^6 times as massive as mercury.
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<span>(-5/6) + c = (-11/12)
c=-11\12+5\6
c=19\12 or 1 7\12</span>
Answer:
C. AAS
Step-by-step explanation:
they share 2 angles(A) you can tell by the markings and they share that one side
by this point you have 2 options left
ASA
or
AAS
the angles are right next to each other so it's AAS
13) b=145 because a line equals 180° so you subtract 35° from 180°
14) b=61 because it as right angle so 90 minus 29 equals 61
15) b= 23 because 360 is a full circle so you add 243 and 94 and get 337 then subtract 337 from 360
16)b=131 because you subtract 49 from 180
17) b=90 because you subtract 90 from 180
18) b=73 because of vertical angles
Step-by-step explanation:
The quadratic equation is x² + (p - 5)x + 2q = 0.
By Vieta's Formula,
we have SOR = -b/a and POR = c/a.
=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.
=> 3 = 5 - p and -18 = 2q
Hence, p = 2 and q = -9.
Alternate Method:
We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.
=> (x + 3)(x - 6) = x² - 3x - 18.
By Comparing Coefficients,
(p - 5) = -3 and 2q = 18.
Hence p = 2 and q = -9.
