3 years ago

Solve for x. (1 point) -ax + 4b > 9

Mathematics

1 answer:

Nataly [62]3 years ago

4 0

It’s going to be x=9, it’s x=9

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How to solve x(x-3)=0

damaskus [11]

Step-by-step explanation:

x(x-3)=0

x=0 or (x-3) =0

x= 0 or x =3

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3 years ago

A = √7 + √c and b = √63 + √d where c and d are positive integers.

mrs_skeptik [129]

Answer:

$\displaystyle a:b=\frac{1}{3}$

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

$a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]$

$b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]$

$\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]$

From [3]:

$9c=d$

Replacing into [2]:

$b=\sqrt{63}+\sqrt{9c}$

We can express 63=9*7:

$b=\sqrt{9*7}+\sqrt{9c}$

Taking the square root of 9:

$b=3\sqrt{7}+3\sqrt{c}$

Factoring:

$b=3(\sqrt{7}+\sqrt{c})$

Find the ration a:b:

$\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}$

Simplifying:

$\boxed{a:b=\frac{1}{3}}$

3 0

3 years ago

Jacob performs the work shown to find tan Tangent 165 degrees. Tangent 165 degrees = negative StartRoot StartFraction 1 + cosine

abruzzese [7]

Answer:

Step-by-step explanation:

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3(x + 1) - (x-3) = 12<br> I need help I don’t I understand

balandron [24]

Answer:

Step-by-step explanation:

3x+3-x+3=12

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2x=6

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3 years ago

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What is [(7x^3)(y^2)]^2/7 in radical form?

GuDViN [60]

Remember
$x^ \frac{m}{n} = \sqrt[n]{x^m}$
and
$(zy)^m=(z^m)(y^m)$
and
(x^m)^n=x^(mn)

so
$((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}$ =
$\sqrt[7]{((7x^3)^2(y^2)^2)}$ =
$\sqrt[7]{((7^2x^6)(y^4))}$ =
$\sqrt[7]{((49x^6)(y^4))}$ =
$\sqrt[7]{49x^6y^4}$

8 0

3 years ago