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Salsk061 [2.6K]

3 years ago

9

Which of these equations have no solution? Check all that apply.

1 answer:

dlinn [17]3 years ago

6 0

First one simplifies to 2x + 6 = 2x + 7 which can't be true so this one has No Solution.
Same applies to the second equation ( 5x + 15 = 5x - 15) No solution

also the last one has no solution because it simplifies to 4x + 20 = 4x + 19

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The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

What is 3/20 as a decimal equivalent

11Alexandr11 [23.1K]

3/20 as a decimal equivalent is <span>0.15</span>

8 0

3 years ago

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What is the product? 3x^5(2x^2+4+1)

const2013 [10]

Answer:

$6x^{7} +15x^{5}$

Step-by-step explanation:

$3x^{5}$ ( $2x^{2} +4+1$ )

Multiply $3x^{5}$ by each term in the parentheses.

$6x^{7}$ + $12x^{5} +3x^{5}$

Now, all you have to do is simplify.

$6x^{7} +15x^{5}$

5 0

3 years ago

Rewrite the following quadratic functions in intercept or factored form. Show your work.

Dmitry [639]

<u>Answer: </u>

f(x) = 3(x+2)(x-2)

<u>Step-by-step explanation: </u>

We are given the following the quadratic function and we are to rewrite it in intercept or factored form:

$f(x) = 3x^2 - 12$

We can factorize the given function so taking the common factors out of it to get:

$f(x)=3x^2 - 12$

$f(x) = 3 (x^2 - 4)$

The term $(x^2-4)$ is in the form $a^2-b^2$ so it can further be factorized to give:

$f(x) = 3 (x+2)(x-2)$

Therefore, the factored form of the given quadratic function is f(x) = 3(x+2)(x-2).

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3 years ago

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Whoever gets it right and first get Brainlest

Ivenika [448]

Answer:

The answer is -5.44

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3 years ago

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