Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
...... I need this as well please help us!!!
The inverse of this function would be f(x) = 
.
You can find the value of any inverse function by switching the f(x) and the x value. Then you can solve for the new f(x) value. The end result will be your new inverse function. The step-by-step process is below.
f(x) = 
- 6 ----> Switch f(x) and x
x = 
- 6 ----> Add 6 to both sides
x + 6 = -----> Take the logarithm of both sides in order to get the f(x) out of the exponent
Log(x + 6) = f(x)Log2 ----> Now divide both sides by Log2
= f(x) ----> And switch the order for formatting purposes.
f(x) =
And that would be your new inverse function.
Answer:
B.x<25
Step-by-step explanation:
Let's solve your inequality step-by-step.
3(x+3)>4(x−4)
Step 1: Simplify both sides of the inequality.
3x+9>4x−16
Step 2: Subtract 4x from both sides.
3x+9−4x>4x−16−4x
−x+9>−16
Step 3: Subtract 9 from both sides.
−x+9−9>−16−9
−x>−25
Step 4: Divide both sides by -1.
−x/
−1
>
−25/
−1
x<25
Answer:
x<25
Answer:
G
Step-by-step explanation:
I did this assignment yesterday
